The terminal velocity as it falls through still air is 4.65154 in/s.
The diameter of small water droplet is 1.25 mil= 1.25×0.0254×10^-3 m
= 3.175 × 10^-5 m
Now the viscosity of still air is η = 1.83× 10⁻⁵ Pa
So the formula for drag force is:
Fd = 6πηrv
where, v is the velocity.
Now to attain terminal velocity acceleration must be zero.
→ W = Fd
ρVg = 6πrηv
ρ × 4/3 πr³×g = 6πrηv
v = 2/9 × ρgr³/ η
v = 2/9 × 10³×9.81×(3.175×10^-3) / 18.6×10^-6
v = 0.1181 m/s
v = 4.65154 in/s
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Okay... so here's what happened;
A huge amount of mass is above you, squeezing down from you from all sides; that's what happened to the hydrogen gas in the core of the sun. It got squeezed together so tightly that four hydrogen nuclei combined to form one helium atom. That's called nuclear fusion. In the process, some of the mass of the hydrogen atoms is converted into energy in the form of light.
:)
Light of the moon is from the light of the sun. So if you're in a certain area where the angle from where your seeing the moon happens to be where the sun's light shines throughout that area. You see a full moon. It's like shining a flashlight on a ball. You move around it and you see half of the light, quarter of the light or even none at all.
<span>When a collision occurs, the change in momentum, is the difference in the momentums of the two objects after the collision minus the momentum of the object before the collision.
From the aforementioned , we have change in momentum to be final momentum after collision - momentum before collision. But then the impulse of the fird bullet is just the change in momentum. Impulse = Ft where F = Ma. Where F= force and a is the acceleration. F = 1000* a; since a = V/t; i. e change in velocity by time. So we have 5000/5 =1000ms^2. Hence F = 1000 * 1000 = 1000000N. Then our Impulse , Ft = 1000000 * 5 = 5000000N.
Momentum just before collision = 1000 * 500 = 500000.
After collision we have final momentum = m * 20 where m is the mass after collsion.
So we have 20M - 500000 = 5000000. 20M = 5000000-500000 = 4500000. M = 225000Kg.</span>
(a) 7.18
The electric field within a parallel plate capacitor with dielectric is given by:
(1)
where
is the surface charge density
k is the dielectric constant
is the vacuum permittivity
The area of the plates in this capacitor is
while the charge is
So the surface charge density is
The electric field is
So we can re-arrange eq.(1) to find k:
(b) 
The surface charge density induced on each dielectric surface is given by
where
is the initial charge density
k = 7.18 is the dielectric constant
Substituting,
And by multiplying by the area, we find the charge induced on each surface:
