To solve this problem it is necessary to apply the concepts related to the adiabatic process that relate the temperature and pressure variables
Mathematically this can be determined as
Where
Temperature at inlet of turbine
Temperature at exit of turbine
Pressure at exit of turbine
Pressure at exit of turbine
The steady flow Energy equation for an open system is given as follows:
Where,
m = mass
= mass at inlet
= Mass at outlet
= Enthalpy at inlet
= Enthalpy at outlet
W = Work done
Q = Heat transferred
= Velocity at inlet
= Velocity at outlet
= Height at inlet
= Height at outlet
For the insulated system with neglecting kinetic and potential energy effects
Using the relation T-P we can find the final temperature:
From this point we can find the work done using the value of the specific heat of the air that is 1,005kJ / kgK
So:
Therefore the maximum theoretical work that could be developed by the turbine is 678.248kJ/kg
The distance the lower spring is stretched from its equilibrium length is 45cm because the weight is 3x as much as the reference spring and the spring constant is the same.
<span>2) The force the bottom spring exerts on the mass is its weight (=mg) PLUS 10.8kg x 3.8m/s^2 = 133N </span>
<span>3) The distance the upper spring is extended from its unstretched length when not accelerated is 15cm </span>
<span>4) Rank the distances the springs are extended from their unstretched lengths: </span>
<span>c) x1 < x2 < x3 </span>
<span>5) The distance the MIDDLE spring is extended from its unstretched length when not accelerated is 45cm </span>
<span>6) Finally, the elevator is moving downward with a velocity of v = -3.4 m/s and also accelerating downward at an acceleration of a = -2.1 m/s2. </span>
<span>a)speeding up </span>
<span>because the v and a are in the same direction</span>
Answer:
Explanation:
From the given information;
Let assume that the distance travelled by the speeder prior to the time the trooper catches with it to be = d
the time interval to be = t
Then, the speeder speed = distance/time
Making distance the subject; then:
distance (d) = speed × time
d = (50 m/s)t
d = 50 t --- (1)
Now, for the trooper; Using the equation of motion:
d = 20t + 1.25t²
Replace the value of d in (1) to the above equation, we have:
50 t = 20 t + 1.25t²
50t - 20t = 1.25t²
30t = 1.25t²
30 = 1.25t
t = 24 seconds
From (1), the distance far down the highway the trooper will travel prior to the time it catches up with the speeder is:
= 50t
= 50(24)
= 1200 seconds
Answer:
76 V/m
Explanation:
= Electric potential at initial location = 119 V
= Electric potential at final location = 43 V
= distance between initial and final location = 1 m
= magnitude of electric field
Magnitude of electric field is given as
= 76 V/m
Answer:
0.
Explanation:
(A) Work done on the dresser which will be given as :
where, F = weight of the dresser = 3500 N
However you can move the dresser, that is a real distance,
Substituting,
(
is the angle at which you apply the force)
