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inessss [21]
3 years ago
8

What force do scientist think is responsible for matter clumping together

Physics
1 answer:
Stells [14]3 years ago
3 0

It MUST be either glue or gravity.

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Light bulbs produce useful energy in the form of light and waste energy in the form of heat. What kind of light bulb would you u
Tatiana [17]

Answer:

C) high efficiency light bulbs, because they produce more heat

4 0
3 years ago
given a circuit powered at 12V with R1, R2, R3 respectively of 10,20,30 Ohm, determine R4 in such a way that the Wheatstone brid
dalvyx [7]

Answer:

The balanced condition for Wheat stones bridge is  

Q

P

​  

=  

S

R

​  

 

as is obvious from the given values.

No, current flows through galvanometer is zero.

Now, P and R are in series, so

Resistance,R  

1

​  

=P+R

=10+15=25Ω

Similarly, Q and S are in series, so

Resistance R  

2

​  

=R+S

=20+30=50Ω

Net resistance of the network as R  

1

​  

 and R  

2

​  

 are in parallel

i=  

R

V

​  

=  

50

6×3

​  

=0.36 A.

Explanation:

8 0
3 years ago
The Kelvin scale is also know as the absolute zero<br> TRUE OR FALSE
Bond [772]

The Kelvin scale is also called absolute zero scale

Explanation:

true

6 0
3 years ago
Calculate the power rating of a home appliance (in kilowatts) that uses 5.1 amps of current when plugged into a 120 Volt outlet.
Mrrafil [7]

Answer:0.612 kilowatts

Explanation:

Current=5.1 amperes

Voltage=120 volts

Power=current x voltage

Power=5.1 x 120

Power=612

power=612 watts

power=612/1000 kilowatts

Power=0.612 kilowatts

4 0
4 years ago
What is the speed vfinal of the electron when it is 10.0 cm from charge 1?
fgiga [73]

Answer:

Two stationary positive point charges, charge 1 of magnitude 3.45 nC and charge 2 of magnitude 1.85 nC, are separated by a distance of 50.0 cm. An electron is released from rest at the point midway between the two charges, and it moves along the line connecting the two charges. What is the speed v(final) of the electron when it is 10.0 cm from

The answer to the question is

The speed v_{final} of the electron when it is 10.0 cm from charge Q₁

= 7.53×10⁶ m/s

Explanation:

To solve the question we have

Q₁ = 3.45 nC = 3.45 × 10⁻⁹C

Q₂ = 1.85 nC = 1.85 × 10⁻⁹ C

2·d = 50.0 cm

a = 10.0 cm

q = -1.6×10⁻¹⁹C

Also initial kinetic energy = 0 and

Initial electric potential energy = k\frac{qQ_1}{d} + k\frac{qQ_2}{d} = kq(\frac{Q_1+Q_2}{d})

Final kinetic energy due to motion = 0.5·m·v²

Final electric potential energy = k\frac{qQ_1}{a} + k\frac{qQ_2}{2d-a} = kq(\frac{Q_1}{a}+\frac{ Q_2}{2d-a})

From the energy conservation principle we have

0+ kq(\frac{Q_1+Q_2}{d})=0.5mv^2+  kq(\frac{Q_1}{a}+\frac{ Q_2}{2d-a})

Solving for v gives

v=\sqrt{\frac{kq(\frac{Q_1+Q_2}{d})-   kq(\frac{Q_1}{a}+\frac{ Q_2}{2d-a})}{0.5m}}

where k = 9.0×10⁹ and m = 9.109×10⁻³¹ kg

gives v =7528188.32769 m/s or 7.53×10⁶ m/s

v_{final} = 7.53×10⁶ m/s

6 0
4 years ago
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