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Yanka [14]
3 years ago
15

We are on an asteroid with thrusters pointed in 4 directions; Go Left, GO Right, Go Up, and Go Down. We start at coordinate (3,3

). We simultaneously fire all 4 thrusters. Go Left 3N, Go Right 4N, Go Up 2N, and Go Down 5N.

Physics
1 answer:
GalinKa [24]3 years ago
7 0
we would be at (4,0)
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A rocket with a total mass of 330,000 kg when fully loaded burns all 280,000 kg of fuel in 250 s. The engines generate 4.1 MN of
lutik1710 [3]

Answer:

6900 m/s

Explanation:

The mass of the rocket is:

m = 330000 − 280000 (t / 250)

m = 330000 − 1120 t

Force is mass times acceleration:

F = ma

a = F / m

a = F / (330000 − 1120 t)

Acceleration is the derivative of velocity:

dv/dt = F / (330000 − 1120 t)

dv = F dt / (330000 − 1120 t)

Multiply both sides by -1120:

-1120 dv = -1120 F dt / (330000 − 1120 t)

Integrate both sides.  Assuming the rocket starts at rest:

-1120 (v − 0) = F [ ln(330000 − 1120 t) − ln(330000 − 0) ]

-1120 v = F [ ln(330000 − 1120 t) − ln(330000) ]

1120 v = F [ ln(330000) − ln(330000 − 1120 t) ]

1120 v = F ln(330000 / (330000 − 1120 t))

v = (F / 1120) ln(330000 / (330000 − 1120 t))

Given t = 250 s and F = 4.1×10⁶ N:

v = (4.1×10⁶ / 1120) ln(330000 / (330000 − 1120×250))

v = 6900 m/s

4 0
3 years ago
How much does approximately a cup of water increase in temperature when heated in a microwave for 45 seconds?
Dovator [93]

Answer:

32 K

Explanation:

A cup of water has a volume of approximately 236 \text{ cm}{}^3. With water having a density of 1 \text{ g/cm}{}^3, the mass of water in a cup is 1 \text{ g/cm}{}^3 \times 236 \text{ cm}{}^3 = 236\text{ g} = 0.236\text{ kg}.

A microwave outputs about 700 W of power. In 45 seconds, the energy expended is 700 \text{ W} \times 45 \text{s} = 31500 \text { J}.

The heat energy supplied to the water is related to the temperature change and the mass of the water by

H = mc\Delta\theta where c is the specific heat capacity of water. This value is c = 4200 \text{ J/kg K}.

\Delta\theta is the temperature change.

\Delta\theta = \dfrac{H}{mc}=\dfrac{31500}{0.236\times4200}=32 \text{ K}

5 0
3 years ago
There has been a lot of attention given to Jupiter’s moon Europa as a possible site where life might be found. What do you think
Vaselesa [24]

Scientists could explore Europa’s oceans by using potent technologically advanced telescopes capable of deciphering the content beneath the ice crust.

<h3>What are potent technologically advanced telescopes?</h3>

The latest technologically advanced telescopes are potent optical devices that allow us to discover the presence of certain compounds not only in the atmosphere of other planets in the solar system but also the content on the surface (e.g, the water content).

These telescopes contain curved mirrors that gather and focus different spectra of light from the sky such as the Webb telescope which was launched by NASA in the final of 2021.

Therefore, with this data, we can see that technologically advanced telescopes are potent optical instruments that can be used to observe the presence of different compounds including water on the surface of a planet or its satellites such as in the case of Europe which is a satellite of Jupiter.

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5 0
1 year ago
Why will a golf ball accelerate faster than a bowling ball when struck by a golf club
Sergio039 [100]
I think you mean velocity. There is only a downward acceleration (gravitational acceleration) for bodies in free-fall, and their acceleration would be the same. So I'm going to assume velocity.

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Modeling this we see:

F*dt = m*v

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4 0
3 years ago
What is the speed of a transverse wave in a rope of length 3.1 m and mass 86 g under a tension of 380 n?
stellarik [79]

The speed of a transverse wave( v) = 117.03 m/s

The formula we can use in this case would be:

v = sqrt (T / (m / l))

Where,

v = is the velocity of the transverse wave = unknown (?)

T = is the tension on the rope = 380 N

m = is the mass of the rope = 86.0 g = 0.086 kg

l = is the length of the rope = 3.1 m

Substituting the given values into the equation to search for the speed v:

v = sqrt (380 N/(0.086 kg /3.1 m))

v = sqrt (380 * 3.1/ 0.086)

v = sqrt (13,697.67)

v = 117.03 m/s

speed of a transverse wave( v) = 117.03 m/s

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4 0
1 year ago
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