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Yanka [14]
3 years ago
15

We are on an asteroid with thrusters pointed in 4 directions; Go Left, GO Right, Go Up, and Go Down. We start at coordinate (3,3

). We simultaneously fire all 4 thrusters. Go Left 3N, Go Right 4N, Go Up 2N, and Go Down 5N.

Physics
1 answer:
GalinKa [24]3 years ago
7 0
we would be at (4,0)
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What do astronomers use in addition to parallax to find the actual distance of stars that are close to Earth?
IgorLugansk [536]

Answer:

trigonometry (guessing)

Explanation:

ellipse: is the shape of an orbit : looks like an oval

periapsis : shortest distance between something like the moon and the planet its orbiting around like the earth

parallax is triangulation. like how gps works. looking at a star one day and then looking at it again 6 months later, an astronomer can see a difference in the viewing angle for the star. With trigonometry, the different angles yield a distance. This technique works for stars within about 400 light years of earth

https://science.howstuffworks.com/question224.htm

By comparing the intrinsic brightness to the star's apparent brightness we can calculate the distance of stars

1/r^2 rule states that the apparent brightness of a light source is proportional to the square of its distance.Jan 11, 2022

https://www.space.com/30417-parallax.html

alternative distance measurement for stars used by most astronomers is the parsec. A star with a parallax angle of 1 arcsecond has a distance of 1 parsec, or 1 parsec per arcsecond of parallax, which is about 3.26 light years

blossoms.mit.edu

.

7 0
2 years ago
A roller coaster speeds up with constant acceleration for 2.3 s until it reaches a velocity of 35 m/s. During this time, the rol
Arada [10]

The initial velocity is 0.65 m/s

Explanation:

The motion of the roller coaster is a uniformly accelerated motion, so we can solve the problem by using the following suvat equation:

s=(\frac{u+v}{2})t

where

s is the displacement

u is the initial velocity

v is the final velocity

t is the time

For the roller coaster in this problem:

v = 35 m/s

t = 2.3 s

s = 41 m

Solving the equation for u, we find the initial velocity:

u=\frac{2s}{t}-v=\frac{2(41)}{2.3}-35=0.65 m/s

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

5 0
3 years ago
Define what is meant by restrictive interventions
zzz [600]
Medical movement for disabilities people
5 0
3 years ago
What is the index of refraction of a material in which the speed of light is 7.50% slower than the speed of light in vacuum?
Inessa [10]

Answer:

The value is n = 1.081

Explanation:

From the question we are told that

   The speed of in a vacuum is c = 3.0 *10^{8} \  m/s

    The speed of light in the material is  v  =  c -0.075c = 0.925 c =  0.925 * 3.0*10^{8}  = 2.775 *10^{8} \ m/s

   Generally the reflection of the material is mathematically represented as

             n = \frac{c}{v}

=>    n = \frac{3.0*10^{8}}{2.775 *10^{8}}

=>    n = 1.081

8 0
3 years ago
An 800-kHz radio signal is detected at a point 2.7 km distant from a transmitter tower. The electric field amplitude of the sign
dimaraw [331]

Answer:

Option D is correct: 170 µW/m²

Explanation:

Given that,

Frequency f = 800kHz

Distance d = 2.7km = 2700m

Electric field Eo = 0.36V/m

Intensity of radio signal

The intensity of radial signal is given as

I = c•εo•Eo²/2

Where c is speed of light

c = 3×10^8m/s

εo = 8.85 × 10^-12 C²/Nm²

I = 3×10^8 × 8.85×10^-12 × 0.36²/2

I = 1.72 × 10^-4W/m²

I = 172 × 10^-6 W/m²

I = 172 µW/m²

Then, the intensity of the radio wave at that point is approximately 170 µW/m²

7 0
3 years ago
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