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Jobisdone [24]
4 years ago
6

What is the displacement of the particle in the time interval 5 seconds to 8 seconds?

Physics
2 answers:
Marizza181 [45]4 years ago
7 0

Answer:

A. 160 meters

B. 80 meters

C. 40 meters

D. 20 meters

E. 0 meters

The correct answer is letter E. 0 meters.

Explanation:

Dmitriy789 [7]4 years ago
3 0
The displacement is the vector with

magnitude
     distance between position at 5 sec and position at 8 sec
and direction
     direction from position at 5 sec to position at 8 sec .

The route followed during the time interval is irrelevant.

      
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The more velocity an object has the harder it is to slow it down

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3 years ago
A car accelerates at a rate of 3 m/s^2. If its original speed is 8 m/s, how many seconds will it take the car to reach a final s
kkurt [141]

Answer:

\Large \boxed{\mathrm{5.67 \ seconds }}

Explanation:

\displaystyle \mathrm{acceleration \ = \ \frac{final \ velocity - initial \ velocity }{elapsed \ time}}

\displaystyle A \ = \ \frac{V_f - V_i }{t}

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4 0
3 years ago
Find the average velocity of the car during the time last three second interval. Answer in units of m/s.
Pani-rosa [81]

Answer:

<u>Average Velocity:</u>

When a body covers some displacement moving from point A to B, in a given time,t. Then dividing the total distance covered by the time taken to complete the displacement is called as the average velocity of that car.

We can calculate the average velocity of car by subtracting the initial displacement of a body,s₁ from  the final displacement position of the body, s₂. And then dividing by the initial time,t₁ been subtracted from the final time,t₂.

  • Δv=x₂-x₁/t₂-t₁,

We will get the required results, now if we want to obtain the results in the final three seconds then, we can have the following explanation to that as given.

Explanation:

Lets say, that we have the car moving for 10 seconds and then it stops at the eleventh second of the trip on final position, of the displacement. Then we divide the whole trips into small segments, as we will have the different velocity at each interval but, the velocity is unknown at the last 3 seconds is unknown=?.  

  • Total time taken, Δt= 11 seconds,
  • Then lets say the velocity at the 8th second is , v=25 m/s,then
  • Δv=x₂-(25)/11-0,⇒Δv=x₂-25/11,
3 0
3 years ago
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