Answer:
18kg dog walking
Explanation:
the dog walking has more inertia than the boy and girl because its gravity is pulling it down to the earth
No matter what direction you throw it, or with what speed, its acceleration is immediately 9.8 m/s^2 downward as soon as you release it from your hand, and it doesn't change until the ball hits something.
Answer:
Explanation:
a ) angular frequency ω =
k is spring constant and m is mass attached
ω = 
= 3.6515 rad / s
frequency of oscillation n = 3.6515 / (2 x 3.14)
= .5814 s⁻¹
x = .1 mcos(ωt)
= .1 mcos(3.6515t)
b ) maximum speed = ωA , A is amplitude
= 3.6515 x .1
= .36515 m /s
36.515 cm /s
maximum acceleration = ω²A
= 3.6515² x .1
= 1.333 m / s²
c ) Kinetic energy at displacement x
= 1/2 m ω²( A²-x²)
potential energy =1/2 m ω²x²
so 1/2 m ω²( A²-x²) = 1/2 m ω²x²
A²-x² = x²
2x² = A²
x = A / √2
The time when the cheetah catches up with the widebeest is 1.53 s
If the initial separation distance approaches zero, it will take the cheetah 1.05 s to catch the widebeest.
The given parameters;
- speed of the wildebeest calf, Vw = 10 m/s
- distance traveled by the calf before the cheetah stands up = 7 m
- constant acceleration of the cheetah, a = 9.5 m/s²
Let the speed of the cheetah = Vc
let the time the cheetah catches up with the wildebeest = t


Apply relative velocity formula to determine the time when the cheetah catches up with the widebeest;
Assuming the wildebeest and the cheetah are running in the same direction;

The time when the cheetah catches up with the widebeest is 1.53 s
If the initial separation distance approaches zero;

Thus, if the initial separation distance approaches zero, it will take the cheetah 1.05 s to catch the widebeest.
Lear more here: brainly.com/question/24430414
Answer:
Explanation:
t=Time airborne=2.54 s
R= horizontal range= 25.5 m
From the projectile motion equations we know that:


H=7.9 m