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stiks02 [169]
4 years ago
14

"A 10.0 mL sample of this solution was transferred to a 500.0-mL volumetric flask and diluted to the mark with water. Then 10.0

mL of the diluted solution was transferred to a 250.0-mL flask and diluted to the mark with water. What is the final concentration of the KNO3 solution?"
Chemistry
1 answer:
Slav-nsk [51]4 years ago
3 0

Answer:

If the original solution is "X" M in KNO₃ (moles/Lt), then final solution will be in concentration (2/250)×X M

Explanation:

Original solution of KNO₃ is X M, then, we take a sample of 10 ml and transferre it to 500 ml:

1000ml=X moles KNO₃

10ml=1/100 X moles KNO₃, that will be in 500ml

We then take 10 ml of this new solution and transferre it to a flask with a final volume of 250ml, so:

500ml=(1/100) X moles KNO₃

10ml=(1/5000) X moles KNO₃, these moles will now be in 250 ml

With this, we can calculate the final concentration (in M, or moles/Lt):

250ml=(X/5000) moles KNO₃

1000ml=2/250×X M KNO₃

So, once you know the original concentration of KNO₃ solution, you should just multiply this number by (2/250) to get final concentration of 250 ml solution obtained by multiple dilutions

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The density of air under ordinary conditions at 25 degrees * C is 1.19g / L . How many kilograms of air are in a room that measu
professor190 [17]

Answer:

33.3 kg of air

Explanation:

This is a problem of conversion unit.

Density is mass / volume

Therefore we have to calculate the volume in the room, to be multiply by density. That answer will be the mass of air.

Volume of the room → 9 ft . 11 ft . 10 ft = 990 ft³

Density is in g/L, therefore we have to convert the ft³ to dm³ (1 dm³ = 1L)

990 ft³ . 28.3 dm³ / 1ft³ = 28017 dm³ → 28017 L

This is the volume of the room, if we replace it in the density formula we can know the mass of air in g.

1.19 g/L = Mass of air / 28017 L

Mass of air = 28017 L .  1.19 g/L → 33340 g of air

Finally, let's convert the mass in g to kg → 33340 g . 1kg / 1000 g = 33.3 kg

5 0
4 years ago
Which substance is the oxidizing agent in this reaction? feo+co→fe+co2 express your answer as a chemical formula?
In-s [12.5K]
In the equation given above, the oxidizing agent is FeO.
An oxidizing agent in a chemical reaction is defined as that substance, which has the capacity to oxidize other substances by gaining electrons from them. In a chemical reaction, an oxidizing agent is usually reduced by gaining electrons.
In the chemical equation given above, iron ll oxide oxidizes carbon monoxide to carbon dioxide. 
6 0
4 years ago
Read 2 more answers
In each reaction box place the best reagent and conditions from the list below benzene 3 boxes
den301095 [7]

Answer : The correct answer is 1) AlCl₃ - CH₃Cl 2) HNO₃ -H₂SO₄ at room temperature 3) Fuming HNO₃ -H₂SO₄ at 90-100 ⁰ C heat .

I think this reaction is forming 2,4,6- trinitrotoluene from benzene, since the product is not mentioned. Following are the steps to convert Benzene to 2,4,6 trinitrotoluene .

Step 1: Conversion of Benzene to Toluene .

Benzene can be converted to toluene by Friedel Craft Alkylation of benzene . In this reaction reagent AlCl₃ and Ch3Cl is used . Electrophile CH³⁺ is produced which attached on carbon of benzene and formation of Toluene and HCl occur.

Benzene     \frac{AlCl3}{Ch3Cl}>   Toulene + HCl

Step 2 : Conversion of Toluene to dinitrotoluene.

Dinitritoluene is prepared from toluene by Nitration . This reaction uses Electrophilic substitution mechanism . The reagents used are HNO₃ and H₂SO₄ at room temperature . These reagents produces NO₂⁺ ( nitronium ion ), a electrophile which attacks on C2 and C4 Carbon atoms of Toluene.

Toluene Tolune   \frac{HNO3 -H2SO4}{30-40 degree C} ->  2,4- dinitrotoluene

Step 3) Conversion of Dinitro toluene to trinitrotoluene.

This reaction is extended nitration of toluene . Further nitration is done in extreme condition . The temperature of reaction is increased to 90- 100 ⁰ C . Due to which there is more production of NO²⁺ ion occurs from HNO₃ -H₂SO₄ and they attack on C6 carbon atom of dinitrotoluene which forms 2,4,6- trinitrotoluene.

Dinitrotoluene 2,4 -dinitrotoluene   \frac{fuming HNO3-H2So4}{90-100 C} ->  2,4,6-trinitrotoluene.

So over all reaction uses three reagents in order :

Benzene  \frac{AlCl3}{CH3Cl}  -> Toluene  \frac{HNO3-H2So4}{room temp}  -> 2,4-dinitrotoluene  \frac{Fuming HNO3 -H2SO4}{Heating at 90-100 C}  -> 2,4,6-trinitrotoluene .

3 0
4 years ago
Read 2 more answers
Need the answer pretttty pleaseeeeee
zhannawk [14.2K]

Answer:

B.) their electrons are assigned to the s and p orbitals only

Explanation:

Once you get to the fourth row on the periodic table, the transition metals are introduced. The transition metals are located in the d-block and their electrons fill up d orbitals. When an element in the p-block (the right side of the table) is in one of these rows, the d-block has to fill up first.

8 0
2 years ago
Iron(III) oxide reacts with carbon monoxide according to the equation: Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g) A reaction mixture initial
Bad White [126]

Answer:

mass of excessive CO = 2.55 gram

Explanation:

Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g)

moles of Fe2O3 = mass / formula mass = 22.00/(56x2+16x3)=0.1375 (mol)

moles of CO = mass / formula mass = 14.1/(16+12) = 0.503

Fe2O3 reacts completely meanwhile CO is excessive.

mass of CO reacts = 3 x nFe2O3 x M = 3 x 0.1375 x (16+12) = 11.55 gram

mass of excessive CO = initial mass - reacted mass = 14.1 - 11.55 = 2.55 gram

4 0
3 years ago
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