Answer:
97.0%m/m es la concentración de la solución
Explanation:
El porcentaje masa/masa (%m/m) se define como 100 veces el radio entre la masa de soluto (300g de HCl) y la masa de la solución. Para hallar la masa de la solución debemos hallar la masa del agua (Solvente) haciendo uso de la ecuación del volumen de un cono. Con el volumen del cono podemos hallar la masa del agua haciendo uso de la densidad, así:
<em>Volumen:</em>
Volumen Cono = π*r²*h / 3
Donde r es el radio = 0.300m
h la altura = 5m
Volumen = π*(5m)²*0.300m / 3
7.85m³
<em>Masa Agua:</em>
7.85m³ * (1.2g / m³) = 9.42g Agua
<em>Masa solución:</em>
300g HCl + 9.42g Agua = 309.42g Solución
<em>%m/m:</em>
300g HCl / 309.42g * 100 =
<h3>97.0%m/m es la concentración de la solución</h3>
Answer:
The molecular formula is SO2F2
Explanation:
Step 1: Data given
Suppose the mass of compound = 100 grams
The compound contains:
31.42 % S = 31.42 grams S
31.35 % O = 31.35 grams O
100 - 31.42 - 31.35 = 37.23 F
Molar mass of S = 32.065 g/mol
Molar mass F = 19.00 g/mol
Molar mass O = 16.00 g/mol
Step 2: Calculate moles
Moles = mass / molar mass
Moles S = 31.42 grams / 32.065 g/mol
Moles S = 0.9799 moles
Moles 0 = 31.35 grams / 16.00 g/mol
Moles 0 = 1.959 moles
Moles F = 37.23 grams / 19.00 g/mol
Moles F = 1.959 moles
Step 3: Calculate mol ratio
We divide by the smallest amount of moles
S: 0.9799 / 0.9799 = 1
F: 1.959/ 0.9799 = 2
O : 1.959 / 0.9799 = 2
The empirical formula is SO2F2
This formula has a molecular mass of 102.06 g/mol
This means the empirical formula is also the molecular formula : SO2F2
hi im breanna
Answer:
The mole is simply a very large number that is used by chemists as a unit of measurement.
Explanation:
The mole is simply a very large number,
6.022
×
10
23
, that has a special property. If I have
6.022
×
10
23
hydrogen atoms, I have a mass of 1 gram of hydrogen atoms . If I have
6.022
×
10
23
H
2
molecules, I have a mass of 2 gram of hydrogen molecules. If I have
6.022
×
10
23
C
atoms, I have (approximately!) 12 grams.
The mole is thus the link between the micro world of atoms and molecules, and the macro world of grams and litres, the which we can easily measure by mass or volume. The masses for a mole of each element are given on the periodic table as the atomic weight. So, if have 12 g of
C
, I know, fairly precisely, how many atoms of carbon I have. Given this quantity, I know how many molecules of
O
2
are required to react with the
C
, which I could measure by mass or by volume.
Answer:
Percent yield of alum is 38.6%
Explanation:
Find attached calculations for detailed explanation.
