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Tju [1.3M]
4 years ago
7

In the reaction HCl + NaOH → NaCl (aq) + H2O , if 45.0 milliliters of a 2.0 M HCl react in an excess of NaOH, how many grams of

H2O will be produced?
Chemistry
1 answer:
BaLLatris [955]4 years ago
4 0
1) HCl + NaOH -> NaCl + H2O

2) 1 mol HCl : 1 mol NaOH: 1 mol NaCl : 1 mol H2O

3) 45.0 ml of 2.0 M HCl => M = n / V => n = M*V = 2.0 M * 0.0450 l = 0.090 moles

4) 0.090 moles of HCl => 0.090 moles of water

molar mass of water = 18.0 g/mol

mass of H2O = moles * molar mass = 0.090 mol * 18.0 g/mol = 1.62 g

Answer: 1.62 g
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15 moles

Explanation:

Data given:

mass of hydrogen (H₂) = 30.0 g

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Solution:

First we look to the reaction in which hydrogen react with oxygen and make (H₂O)

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              2H₂  + O₂  -----------> 2H₂O

Now look at the reaction for mole ratio

             2H₂  + O₂  -----------> 2H₂O

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As we Know

molar mass of H₂  = 2(1) = 2 g/mol

molar mass of H₂O = 2(1) + 16 = 18 g/mol

Now convert moles to gram

                  2H₂         +       O₂        ----------->    2H₂O

          2 mole (2 g/mol)                                 2 mole (18 g/mol)

                    4 g                                                     36 g

So,

we come to know that 4 g of hydrogen gives 36 g of water then how many grams of water will be produce by 30 grams of hydrogen.

Apply unity formula

                       4 g of H₂ ≅ 36 g of H₂O

                        30 g of H₂ ≅ X of H₂O

Do cross multiplication

                  X of H₂O =  30 g x 36 g / 4 g

                  X of H₂O =  270 g

Now convert grams of H₂O into moles

               No. of moles = mass in grams/molar mass

Put values in above formula

               No. of moles = 270 g / 18 (g/mol)

               No. of moles = 15 mol

so 30 gram of hydrogen produce 15 mol of water.

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