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Tju
[1.3M]
3 years ago
7
In the reaction HCl + NaOH → NaCl (aq) + H2O , if 45.0 milliliters of a 2.0 M HCl react in an excess of NaOH, how many grams of
H2O will be produced?
Chemistry
Answer
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1
answer:
BaLLatris
[955]
3 years ago
4
0
1) HCl + NaOH -> NaCl + H2O
2) 1 mol HCl : 1 mol NaOH: 1 mol NaCl : 1 mol H2O
3) 45.0 ml of 2.0 M HCl => M = n / V => n = M*V = 2.0 M * 0.0450 l = 0.090 moles
4) 0.090 moles of HCl => 0.090 moles of water
molar mass of water = 18.0 g/mol
mass of H2O = moles * molar mass = 0.090 mol * 18.0 g/mol = 1.62 g
Answer: 1.62 g
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