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Leni [432]
3 years ago
5

A clear, pure liquid sample is brought into the lab and exposed to an electrical current. Different gases are produced on each o

f the electrodes. The sample is -
(4 points)
a. a polymer
B. an element
c. a compound
D. an alloy
Chemistry
1 answer:
aleksklad [387]3 years ago
4 0
It would be a compound.
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27 g of Al will react with how much mass of O2 to produce Al2O3
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24g 4Al+3O2=2Al2O3
27g x(g)
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The photo shows wires made of pure copper, an element,
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I can’t see the picture but a atom I think
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A sample of helium gas has a pressure of 1.5 atm at 23 C. At what Celsius
Nina [5.8K]

Answer:

180.87 °C

Explanation:

Applying pressure law,

P/T = P'/T'..................... Equation 1

Where P = Initial pressure of helium gas, T = Initial Temperature of helium gas, P' = Final Pressure of helium gas, T' = Final Temperature of helium gas

Make T' the subject of equation 1

T' = P'T/P......................... Equation 2

From the question,

Given: P = 1.5 atm, P' = 2.3 atm, T = 23°C = (23+273)K = 296 K

Substitute these values into equation 2

T' = (2.3×296/1.5)

T' = 680.8/1.5

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T' = 180.87°C

3 0
3 years ago
Different between chlorine and chloride​
ZanzabumX [31]
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4 0
3 years ago
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Four gases were combined in a gas cylinder with these partial pressures: 3.5 atm N2, 2.8 atm O2, 0.25 atm Ar, and 0.15 atm He. W
liq [111]

The total pressure is 6.7 atm.  The mole fractions of O₂ and Ar are 0.42 and 0.037.

<em>p</em>(Tot) = <em>p</em>(N₂) + <em>p</em>(O₂) + <em>p</em>(Ar) + <em>p</em>(He) = 3.5 atm + 2.8 atm + 0.25 atm + 0.15 atm = 6.7 atm

χ(O₂) = p(O₂)/p(Tot) = 2.8 atm/6.7 atm = 0.42

χ(Ar) = p(Ar)/p(Tot) = 0.25 atm/6.7 atm = 0.037

6 0
4 years ago
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