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Leni [432]
3 years ago
5

A clear, pure liquid sample is brought into the lab and exposed to an electrical current. Different gases are produced on each o

f the electrodes. The sample is -
(4 points)
a. a polymer
B. an element
c. a compound
D. an alloy
Chemistry
1 answer:
aleksklad [387]3 years ago
4 0
It would be a compound.
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Refer to your periodic table:
Mazyrski [523]

iondine

Explanation:

bromine has 185pm, astatine haa 200, iondine has 140 and lastly fluorine has 147. so iondine has the smallest atomic radius

6 0
3 years ago
What is the molality of a solution of 12.9 g of fructose (C6H12O6) in 31.0 g of water?
jasenka [17]

Answer:

2.31 m C₆H₁₂O₆

Explanation:

Hope this helps

8 0
2 years ago
What is the wavelength (in nm) of
LenKa [72]

Answer:

λ = 0.45×10⁻⁶ m

Explanation:

Given data:

Wavelength of blue light = ?

Frequency of blue light = 6.69×10¹⁴ s⁻¹

Solution:

Formula;

Speed of wave = wavelength × frequency

Speed of wave = 3.00×10⁸ m/s

by putting vales,

3.00×10⁸ m/s = λ × 6.69×10¹⁴ s⁻¹

λ = 3.00×10⁸ m/s / 6.69×10¹⁴ s⁻¹

λ = 0.45×10⁻⁶ m

6 0
2 years ago
Which physical method can be used for obtaining a sample of salt from a small beaker of salt water? boiling freezing filtration
sergij07 [2.7K]
I think it's boiling :)
3 0
2 years ago
Read 2 more answers
Convert 5.28 x 1019 molecules of C6H1206 to grams.
nlexa [21]

Answer:

m=0.0158g

Explanation:

Hello there!

In this case, it is possible to comprehend these mass-particles problems by means of the concept of mole, molar mass and the Avogadro's number because one mole of any substance has 6.022x10²³ particles and have a mass equal to the molar mass.

In such a way, for C₆H₁₂O₆, whose molar mass is about 180.16 g/mol, the referred mass would be:

m=5.28x10^{19}molecules*\frac{1mol}{6.022x10^{23}molecules}*\frac{180.16g}{1mol}\\\\m=0.0158g

Best regards!

5 0
3 years ago
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