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Stolb23 [73]
3 years ago
8

Write molecular, complete ionic, and net ionic equations for the reactions that occur, if any, when solutions of the following s

ubstances are mixed:
calcium nitrate and sodium sulfate
Chemistry
1 answer:
Stells [14]3 years ago
5 0
<span>Ca(NO3)2 (aq) + Na2SO4 (aq) --> CaSO4 (s) + 2NaNO3 (aq) Ca2+ (aq) + 2NO3- (aq) + 2 Na+ (aq) + SO4 (aq) --> CaSO4 (s) + 2Na+ (aq) + 2NO3- (aq) cancel out spectator ions Ca2+ (aq) + SO4 (aq) ---> CaSO4 (s hope it helps</span>
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Assign each species to the expression that most accurately describes the basic units of that substance. categories: single atoms
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6 0
3 years ago
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14 points!!! Pls tell me answer :3
iren [92.7K]
I’d say the last one
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Aqueous lithium sulfate was mixed with aqueous strontium chlorate, and a crystallized strontium sulfate product was formed. cons
Dmitriy789 [7]

Lithium sulfate is Li2SO4

Strontium chlorate is Sr(ClO3)2

Strontium sulfate is SrSO4

 

So the complete balanced chemical reaction for this is:

 

Li2SO4 (aq) +  Sr(ClO3)2 (aq) -->  SrSO4 (s)  +  2 LiClO3 (aq)

 

 

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4 0
3 years ago
Pressure is this sample?
faltersainse [42]

Answer:

P = 164 Atm

Explanation:

PV = nRT => P = nRT/V

n = 10.0 moles

R = 0.08206 L·Atm/mol·K

T = 27.0°C = 300 K

V = 1.50 Liters

P = (10.0 mol)(0.08206 L·Atm/mol·K )(300 K)/(1.50 Liters) = 164.12 Atm ≅ 164 Atm (3 sig. figs.)

5 0
3 years ago
Calculate the number of liters in 3.25 g of ammonia
il63 [147K]

 The liters in   3.25 g   of  ammonia  4.28 L


  <u><em>calculation</em></u>

 Step 1: find moles of ammonia

 moles = mass÷ molar  mass

 From  periodic    table  the molar mass  of ammonia (NH₃)  =  14 +(1×3 ) = 17  g/mol

3.25 g÷ 17 g/mol = 0.191   moles

Step 2: find the number of liters of ammonia

 that is at STP  1  moles = 22.4 L

                        0.191 moles = ? L

<em>by cross  multiplication</em>

 ={( 0.191   moles  ×22.4 L) / 1 mole}  = 4.28 L



8 0
3 years ago
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