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Stolb23 [73]
3 years ago
8

Write molecular, complete ionic, and net ionic equations for the reactions that occur, if any, when solutions of the following s

ubstances are mixed:
calcium nitrate and sodium sulfate
Chemistry
1 answer:
Stells [14]3 years ago
5 0
<span>Ca(NO3)2 (aq) + Na2SO4 (aq) --> CaSO4 (s) + 2NaNO3 (aq) Ca2+ (aq) + 2NO3- (aq) + 2 Na+ (aq) + SO4 (aq) --> CaSO4 (s) + 2Na+ (aq) + 2NO3- (aq) cancel out spectator ions Ca2+ (aq) + SO4 (aq) ---> CaSO4 (s hope it helps</span>
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What is the molarity of a solution that is 26.0% by mass in phosphoric acid, H3PO4, and that has a density of 1.155 g/mL?
steposvetlana [31]

Answer: The molarity of a solution that is 26.0% by mass in phosphoric acid is 3.06 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

n = moles of solute

V_s =volume of solution in ml

Given : 26.0 g of phosphoric acid in 100 g of solution.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{26.0g}{98g/mol}=0.265moles

Volume of solution =\frac{\text {Mass of solution}}{\text {Density of solution}}=\frac{100g}{1.155g/ml}=86.6ml

Molarity=\frac{0.265\times 1000}{86.6ml}=3.06M

Molarity of a solution that is 26.0% by mass in phosphoric acid is 3.06 M

8 0
3 years ago
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natulia [17]

Answer:

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Explanation:

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3 years ago
What is the interaction between two charged particles called?
Roman55 [17]
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5 0
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3 years ago
The mass of a deuterium nucleus 21H is less than its components masses. Calculate the mass defect.________ amu
Inessa [10]

Answer:

The mass defect of a deuterium nucleus is 0.001848 amu.

Explanation:

The deuterium is:

^{A}_{Z}X \rightarrow ^{2}_{1}H  

The mass defect can be calculated by using the following equation:

\Delta m = [Zm_{p} + (A - Z)m_{n}] - m_{a}

Where:

Z: is the number of protons = 1

A: is the mass number = 2      

m_{p}: is the proton's mass = 1.00728 amu  

m_{n}: is the neutron's mass = 1.00867 amu

m_{a}: is the mass of deuterium = 2.01410178 amu

Then, the mass defect is:

\Delta m = [1.00728 amu + (2- 1)1.00867 amu] - 2.01410178 amu = 0.001848 amu

Therefore, the mass defect of a deuterium nucleus is 0.001848 amu.

I hope it helps you!  

5 0
3 years ago
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