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Stolb23 [73]
3 years ago
8

Write molecular, complete ionic, and net ionic equations for the reactions that occur, if any, when solutions of the following s

ubstances are mixed:
calcium nitrate and sodium sulfate
Chemistry
1 answer:
Stells [14]3 years ago
5 0
<span>Ca(NO3)2 (aq) + Na2SO4 (aq) --> CaSO4 (s) + 2NaNO3 (aq) Ca2+ (aq) + 2NO3- (aq) + 2 Na+ (aq) + SO4 (aq) --> CaSO4 (s) + 2Na+ (aq) + 2NO3- (aq) cancel out spectator ions Ca2+ (aq) + SO4 (aq) ---> CaSO4 (s hope it helps</span>
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Convert 4.92 L of hydrogen at STP to moles.
Lorico [155]

{\huge{\fcolorbox{yellow}{red}{\orange{\boxed{\boxed{\boxed{\boxed{\underbrace{\overbrace{\mathfrak{\pink{\fcolorbox{green}{blue}{Answer}}}}}}}}}}}}}

\sf C) \:  0.220 \: mol \: H_2

Explanation:

1 mol = 22.4 litres

4.92 = how many moles?

\sf  \implies  \frac{4.92}{22.4}  \\  \\  \sf  \implies 0.2196 \\  \\  \sf  \implies 0.220 \: mol \: H_2

5 0
2 years ago
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Neutralization Reactions
PolarNik [594]

Answer:

its a option neutralization takes place between acid and base plz mark me branliest

3 0
2 years ago
Which substance is liquid at 0°C? 1. alcohol 2. aluminum 3. ammonia 4. copper
Tanya [424]
Alcohol, alcohol is the only liquid  since copper and aluminum are a solid ammonia is a bacteria
5 0
3 years ago
Calculate the standard cell potential of the following cell at 25°C. Sn(s) | Sn2+(aq) || Cu2+(aq) | Cu(s).
Semmy [17]

Answer:

0.48 V

Explanation:

Usually in the cell notation, the left side shows oxidation. So,

Oxidation half reaction:

Sn_{(s)}\rightarrow Sn^{2+}_{(aq)}+2e^-    E^o_{ox}=-E^o_{red}=-(-0.14\ V)=0.14\ V

Reduction half reaction:

Cu^{2+}_{(aq)}+2e^-\rightarrow Cu_{(s)}    E^o_{red}=0.34\ V

E^o_{cell}=E^o_{ox}+E^o_{red}= (0.14+0.34)\ V=0.48\ V

4 0
3 years ago
A projectile is fired with speed v0 at an angle theta from the horizontal from the horizontal as shown in the figure.
irga5000 [103]

Answer:

v₀ = √(2gH/(sin²θ)) = (sin θ)√(2gH)

v₀ = √(gR/(sin2θ))

Explanation:

An image of the artillery officer, the hill and path of motionof the projectile is attached to this solution.

Given, R, H, g and θ (theta)

Using the equations of motion, we can get the initial velocity v₀

First of, we need to resolve this motion into the vertical and horizontal axis.

The horizontal component of the initial velocity, v₀ₓ = v₀ cos θ

Vertical component of the initial velocity, v₀ᵧ = v₀ sin θ

When the projectile reaches maximum height, Velocity at max height, vₕ = 0m/s

From equations of motion,

vₕ = v₀ᵧ - gt

0 = v₀ sinθ - gt

t = v₀ sinθ/g

This is the time taken to reach maximum height. The time take to comolete the toyal flight, T = 2t = (2v₀ sinθ)/g

The maximum height to be reached, H can be calculated from the equations of motion too

H = vₕt - 0.5gt² = 0 - 0.5g((v₀ sinθ)/g)²

H = (0.5g v₀² sin²θ)/g²

H = (v₀² sin²θ)/2g

The range, or horizontal distance to be covered by the projectile, R, will be calculated using the horizontal component of the initial Velocity, v₀ₓ = v₀ cos θ, this horizontal velocity is constant all through the motion, so, no acceleration in the horizontal direction.

R = v₀ₓT =  (v₀ cos θ)((2v₀ sinθ)/g)

R = (v₀²(2cosθsinθ)/g)

2cosθsinθ = sin2θ

R = v₀²(sin2θ)/g

So, writing v₀ in terms of all the other parameters,

v₀ = √(2gH/(sin²θ)) =  (sinθ)√(2gH

v₀ = √(gR/(sin2θ))

4 0
3 years ago
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