Raw one valid lewis structure (including all lone pair electrons and any formal charges) for ch2n2. Assume the atoms are arrange
d as shown below. H c n n h
1 answer:
In the <em>trial structure</em> (1st image below), every atom has an octet.
Valence electrons = 20
Valence electrons available = 4 + 2 +10 = 16
The trial structure has 4 electrons too many. The actual structure must have <em>two double bonds or one triple bond.</em>
The second image shows two possible Lewis structures.
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Answer:
Explanation:
Using Laplace's law of surface tension:
where:
P = pressure
T = surface tension
r = radius
In the longer alveoli with radius of 0.07 mm = ; we have:
P =
P =
In the smaller alveoli with radius 0.05 mm = ; we have:
P =
P =
The pressure difference can now be calculate as follows:
Pressure difference =
Pressure difference =