Raw one valid lewis structure (including all lone pair electrons and any formal charges) for ch2n2. Assume the atoms are arrange
d as shown below. H c n n h
1 answer:
In the <em>trial structure</em> (1st image below), every atom has an octet.
Valence electrons = 20
Valence electrons available = 4 + 2 +10 = 16
The trial structure has 4 electrons too many. The actual structure must have <em>two double bonds or one triple bond.</em>
The second image shows two possible Lewis structures.
You might be interested in
Answer:
Halogens or Nitrogen.
Explanation:
