Answer:
O₂; KCl; 33.3
Explanation:
We are given the moles of two reactants, so this is a limiting reactant problem.
We know that we will need moles, so, lets assemble all the data in one place.
2KCl + 3O₂ ⟶ 2KClO₃
n/mol: 100.0 100.0
1. Identify the limiting reactant
(a) Calculate the moles of KClO₃ that can be formed from each reactant
(i)From KCl
(ii) From O₂
O₂ is the limiting reactant, because it forms fewer moles of the KClO₃.
KClO₃ is the excess reactant.
2. Moles of KCl left over
(a) Moles of KCl used
(b) Moles of KCl left over
n = 100.0 mol - 66.67 mol = 33.3 mol
Answer:
See explanation below
Explanation:
The melting point (the temperature that it changes from solid to liquid) of a pure substance depends on its mass, the forces between its molecules, and the pressure of the system.
The melting point, or the freezing point, of a mixture, is a temperature between the melting point of its components. Salt has a huge negative melting point, so when it is added to the water, the melting point decreases from 0ºC to -21ºC approximately.
So, the water will only freeze again if the temperature becomes below -21ºC which is very difficult to happen.
Answer:
0.9307 moles have been introduced into the bag.
Explanation:
Pressure of the gas within the bag,P = 1.00 atm
Temperature of the gas remains at room temperature,T=20.0 °C = 293.15 K
Volume of the gas in the bag = V = 22.4 L
Number of moles of gas = n
Using an ideal gas equation:
n = 0.9307 moles
0.9307 moles have been introduced into the bag.
Cells are the basic unit of structure in all organisms and also the basic unit of reproduction.
What is the this (^ that up there) a description of?
Answer:
pH = - log [2.12 x 10^-3]
what is the log of 2.22 x 10^-3]
Take the opposite of that,
That is the pH, now, just make certain you use the correct significant figures.
Explanation:
