Answer:
Nutrition has a significant impact on numerous reproductive functions including hormone production, folliculogenesis, fertilization, and early embryonic development
Explanation:
This intimate association is because reproductive processes are energetically expensive, and the brain must temper the fertility of individuals to match nutritional availability.Reproduction function in mammals can be inhibited when food availability is low or when increased energy demands are not met by compensatory food intake such as in short-term and chronic withdrawal of nutrients.This very close alignment with the food supply is more important in females, where pregnancy and lactation are linked to considerable energetic expenses, needed for the nurture of embryos and newborns. In fact, her reproductive outcome can be seriously altered and even life threatening to both the mother and offspring when nutritional imbalance occurs. In order to keep constant body energy stores, in mammals, a series of homeostatic events leading to maintenance of energy balance are activate when a state of energy scarcity or abundance occurs.
Answer:
Amount left after 25 days = 12.5 g
Explanation:
Given data:
Mass of sample = 400 g
Half life of sample = 5 days
Mass left after 25 days = ?
Solution:
First of all we will calculate the number of half lives passes in given time period.
Number of half lives = Time elapsed / Half life
Number of half lives = 25 days/ 5 days
Number of half lives = 5
At time zero = 400 g
At 1st half life = 400 g/2 = 200 g
At 2nd half life = 200 g/2 = 100 g
At 3rd half life = 100 g/2 = 50 g
At 4th half life = 50 g/2 = 25 g
At 5th half life = 25 g/2 = 12.5 g
The pH of the solution : 12
<h3>Further explanation</h3>
Reaction
HCOOH + NaOH ⇒ HCOONa + H₂O
mol HCOOH =
mol NaOH =
Mol NaOH>mol HCOOH ⇒ at the end of the reaction there will be a strong base remains from mol NaOH, so that the pH is determined from [OH⁻]
ICE method :
HCOOH + NaOH ⇒ HCOONa + H₂O
4 5
4 4 4 4
0 1 1 1
Concentration of [OH⁻] from NaOH :
pOH=-log[OH⁻]
pOH=-log 10⁻²=2
pH+pOH=14
pH=14-2=12
Answer:
Explanation:
Number of moles of CuCl2 initially present = volume * molar concentration
= 0.134 * 8
= 1.072 mol.
Molar mass of CuCl2 = 63.5 + (2*35.5)
= 134.5 g/mol
Mass of CuCl2 = molar mass * number of moles
= 134.5 * 1.072
= 144.184 g
Mass of CuCl2 in 48 ml = 5.89 g in 48 ml
Volume = 5.89 * (48/144.184)
= 1.96 ml.
