Answer: 16.32 g of 
as excess reagent are left.
Explanation:
To calculate the moles :
According to stoichiometry :
2 moles of 
require = 1 mole of
Thus 0.34 moles of will require=
of
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
Moles of left = (0.68-0.17) mol = 0.51 mol
Mass of 
Thus 16.32 g of as excess reagent are left.
For metamorphism of rock to occur, temperature and pressure must
increase. Rocks created in this manner are called metamorphic
rocks.
The AP Biology teacher is measuring out 638.0 g of dextrose (C6H12O6) for a lab the moles of dextrose is this equivalent to is 3.6888 moles.
<h3>What are moles?</h3>
A mole is described as 6.02214076 × 1023 of a few chemical unit, be it atoms, molecules, ions, or others. The mole is a handy unit to apply due to the tremendous variety of atoms, molecules, or others in any substance.
To calculate molar equivalents for every reagent, divide the moles of that reagent through the moles of the restricting reagent. The calculation is follows:
- 655/12 x 6 + 12+ 16 x 6
- = 655/ 180 = 3.6888 moles.
Read more about moles:
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Answer:
SbcI3
Explanation:
The symbol of antimony is 'Sb'.
The symbol of chlorine is 'Cl'
First write down the symbol of the first element.
Use the prefix to determine the atoms of first element. If there is no prefix on element then there is only 1 atom.
Now write down the symbol of the second element.
Use the prefix to determine the atoms of second element.
Use prefix as 'mono' for '1', 'di' for '2', 'tri' for '3' and so on.
