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swat32
4 years ago
6

Write an equation for a line perpendicular to the x-axis that passes through the point (5,1)

Mathematics
1 answer:
natka813 [3]4 years ago
6 0
If it is perpendicular to the x-axis, it is a vertical line of the form:

x=k, since it must pass through (5,1) that vertical line is:

x=5
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How many solutions does each equation have?
NikAS [45]
1.
2x-2=2x+32x-2=2x+3
notice
2x-3=2x+2
minus 2x both sides
-3=2
false
no solution

2. 5m-4=7m+85m-4
add 4 to both sides
5m=92m
therefor m=0
but wait
5m-4=7m+8
5(0)-4=7(0)+8
-4=8
false
no solution


3.
y+7=y-3
minus y both sides
7=-3
false
no solution



none of them have solutions
7 0
3 years ago
Please help me with this Solve. 6 1/3+k+3 5/6+5 1/2=26 1/6 A. 10 1/2 B. 9 1/2 C. 10 1/6 D. 11 1/2
cupoosta [38]
1. Rename the mixed numbers with common denominators
2. Add the mixed numbers together to get 15 4/6
3. Subtract the sum from 26 to get 10 1/2
4. Since the only term left on the left is k so k=10 1/2
6 0
4 years ago
Find the 6th term of the expansion of (2p - 3q)11. a. -7,185,024p4q7 c. -7,185p4q7 b. -7,185,024p6q5 d. -7,185p6q5
bezimeni [28]
\bf (2p-3q)^{11}\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&&(2p)^{11}(-3q)^0\\
2&+11&(2p)^{10}(-3q)^1\\
3&+55&(2p)^9(-3q)^2\\
4&+165&(2p)^8(-3q)^3\\
5&+330&(2p)^7(-3q)^4\\
6&+462&(2p)^6(-3q)^5
\end{array}

the coefficient for the first term is 1, the next is 11 and so on... now, notice, the elements of the binomial, the 1st element starts off with 11, and every term it goes down by 1, the 2nd element starts off at 0, and goes up by 1 in each term.

now, to get the next coefficient, you simply, "get the product of the current coefficient and the exponent of the 1st element, and divide that by the exponent of the 2nd element in the next term".

for example, how did we get 165 for the 4th term.... well  (55*9)/3

how did we get 462 for the 6th term? well (330*7)/5.

and then you can just expand it from there.
8 0
3 years ago
Read 2 more answers
A pair of dice are rolled. What is the probability of rolling 6 or less?
Allushta [10]

Answer:

1/36

Step-by-step explanation:

The probability of rolling a number less than 6 or 6 itself on one die is 1/6. A pair of dice would be the combined probability 1/6*1/6 which is 1/36. So there's a 1/36 chance of having both dice roll numbers less than 6 or 6 itself.

6 0
3 years ago
Given the function f(x)=-8x2+8x+9,state whether the vertex represents a maximum or minimum point for the function.
Lelechka [254]
8x2+8x+9
=16x+8x+9
=24x+9
Are that right
5 0
3 years ago
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