Answer:
Time of flight A is greatest
Explanation:
Let u₁ , u₂, u₃ be their initial velocity and θ₁ , θ₂ and θ₃ be their angle of projection. They all achieve a common highest height of H.
So
H = u₁² sin²θ₁ /2g
H = u₂² sin²θ₂ /2g
H = u₃² sin²θ₃ /2g
On the basis of these equation we can write
u₁ sinθ₁ =u₂ sinθ₂=u₃ sinθ₃
For maximum range we can write
D = u₁² sin2θ₁ /g
1.5 D = u₂² sin2θ₂ / g
2 D =u₃² sin2θ₃ / g
1.5 D / D = u₂² sin2θ₂ /u₁² sin2θ₁
1.5 = u₂ cosθ₂ /u₁ cosθ₁ ( since , u₁ sinθ₁ =u₂ sinθ₂ )
u₂ cosθ₂ >u₁ cosθ₁
u₂ sinθ₂ < u₁ sinθ₁
2u₂ sinθ₂ / g < 2u₁ sinθ₁ /g
Time of flight B < Time of flight A
Similarly we can prove
Time of flight C < Time of flight B
Hence Time of flight A is greatest .
Answer:
0.119 s
Explanation:
Given that

Lets take final speed of the softball after covering 4.8 m = V
We know that

Also We know that

Putting the value of V ,U and a in the previous equation We get

Therefore slide time will be 0.119 s
Answer:
the speed of the waves is 150 cm/s
Explanation:
Given;
frequency of the wave, f = 10 Hz = 10
distance between 4 nodes, L = 15.0 cm
The wavelength (λ) of the wave is calculated as follows;
Node to Node = λ/2
L = 2(Node to Node) = (4 Nodes) = 2 (λ/2) = λ
Thus, λ = L = 15.0 cm
The speed (v) of the wave is calculated as follows;
v = fλ
v = 10 Hz x 15.0 cm
v = 150 cm/s
Therefore, the speed of the waves is 150 cm/s
Answer:
The value of third charge is 0.8μC.
Explanation:
Given that.
Magnitude of net force=4.444 N
According to figure,
Suppose, First charge = 2.4 μC
Second charge = 6.2 μC
Distance r₁ = 9.8 cm
Distance r₂ = 2.1 cm
We need to calculate the value of r
Using Pythagorean theorem

Put the value into the formula


We need to calculate the force
Using formula of force

Force F₁₂,



Force F₂₃,

We need to calculate the value of third charge





Hence, The value of third charge is 0.8μC.