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Sidana [21]
3 years ago
13

Would the springs inside a bathroom scale be more compressed or less compressed if you weighed yourself in an elevator that was

moving upward at constant velocity
Physics
1 answer:
Ber [7]3 years ago
6 0
More compressed. moving up = apparent weight (i.e., your norma force) is greater. this means you’ll weighr more and push those springs down even more than you would at rest.
You might be interested in
A sand mover at a quarry lifts 2,000 kg of sand per minute a vertical distance of 12 m. The sand is initially at rest and is dis
Marianna [84]

Answer:

<h2>E. 3.95kW</h2>

Explanation:

Power is defined as the rate of workdone.

Power = Workdone/time taken

Given Workdone = Force * distance

Power = Force * distance/time taken

Power = mgd/t (F = mg)

m = mass of the sand in kg

g = acceleration due to gravity in m/s²

d = vertical distance covered in metres

t = time taken in seconds

Given m = 2000kg, d = 12m, t = 1min = 60secs, g = 9.8m/s²

Power = 2000*9.8*12/60

Power = 3920Watts

Minimum rate of power that must be supplied to this machine is 3920Watts or 3.92kW

5 0
3 years ago
You may have noticed runaway truck lanes while driving in the mountains. These gravel-filled lanes are designed to stop trucks t
Sladkaya [172]

Answer:

0.767

Explanation:

The work done on the truck by the frictional drag force is given by

W=-Fd

where

F is the magnitude of the frictional force

d = 38.0 m is the maximum displacement allowed for the truck

The negative sign is due to the fact that the force of friction is opposite to the motion of the truck

The force of friction can also be written as:

F=\mu mg

where

\mu is the coefficient of kinetic friction between the truck and the lane

m is the mass of the truck

g is the acceleration of gravity

So we can rewrite the work done as

W=-\mu mg d (1)

According to the work-energy theorem, the work done by friction is equal to the change in kinetic energy of the truck:

W=K_f - K_i = \frac{1}{2}mv^2-\frac{1}{2}mu^2 (2)

where

v = 0 is the final velocity of the truck

u = 23.9 m/s is the initial velocity of the truck

By combining (1) and (2) we get

-\frac{1}{2}mu^2 = -\mu mg d

And solving for \mu, we find the minimum coefficient of kinetic friction able to stop the truck in a distance d:

\mu = \frac{u^2}{2gd}=\frac{23.9^2}{2(9.8)(38.0)}=0.767

7 0
3 years ago
Give 5 real life examples of a tension​
Delvig [45]

<em><u>1.car</u></em><em><u> </u></em><em><u>towing</u></em>

<em><u>2.pulling</u></em><em><u> </u></em><em><u>bucket</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>water</u></em>

<em><u>3.gym</u></em><em><u> </u></em><em><u>equipment</u></em><em><u> </u></em>

<em><u>4.crane</u></em><em><u> </u></em><em><u>machine</u></em>

<em><u>5.tug</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>war</u></em>

6 0
2 years ago
. Light travels at a speed of about 300 000 km/s. a. Express this value in scientific notation. b. Convert this value to meters
olganol [36]

Answer:

The answer to your question is below

Explanation:

Data

light speed = 300 000 km/s

a) Express it in scientific notation

to do it, we just move the decimal point 5 places to the left

         300 000 = 3.0 x 10 ⁵ km/s

b) Convert this value to meters per hour

  (300 000 km/s)(1000 m/1 km)(3600 s/1 h) = 300000x1000x3600 / 1x1x1

                                                                        = 1.08 x 10¹² m/h

c) What distance in centimeters does light travel in 1 s?

data

v = 300 000 km/s

d = ?

t = 1 s

 formula   v = d/t      we clear distance     d = vxt

                                  d = 300000 x 1 = 300000 km

                                   d = 300000000 m = 30000000000 cm

4 0
4 years ago
A honeybee with a mass of 0.150 g lands on one end of a floating 4.75-g popsicle stick, as shown in (Figure 1) . After sitting a
Alekssandra [29.7K]

Answer:

0.0443 m/s

Explanation:

m_1 = Mass of honeybee = 0.15 g

m_2 = Mass of popsicle stick = 4.75 g

v_1 = Velocity of honeybee

v_2 = Velocity of stick = 0.14 cm/s

In this system the linear momentum is conserved

m_1v_1=m_2v_2\\\Rightarrow v_1=\dfrac{m_2v_2}{m_1}\\\Rightarrow v_1=\dfrac{4.75\times 0.14}{0.15}\\\Rightarrow v_1=4.43\ m/s

The velocity of the bee is 4.43 cm/s or 0.0443 m/s

5 0
3 years ago
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