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Sidana [21]
2 years ago
13

Would the springs inside a bathroom scale be more compressed or less compressed if you weighed yourself in an elevator that was

moving upward at constant velocity
Physics
1 answer:
Ber [7]2 years ago
6 0
More compressed. moving up = apparent weight (i.e., your norma force) is greater. this means you’ll weighr more and push those springs down even more than you would at rest.
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If B is added to C, the result is a vector in the direction of the positive y-axis with a magnitude equal to that of If C = zi +
fredd [130]

Answer:c

Explanation:

4 0
3 years ago
CAN SOMEONE PLEASE HELP ME WITH MY PHYSICS QUESTIONS? I NEED CORRECT ANSWERS ONLY!
BARSIC [14]
<h2>Right answer: acceleration due to gravity is always the same </h2><h2 />

According to the experiments done and currently verified, in vacuum (this means there is not air or any fluid), all objects in free fall experience the same acceleration, which is <u>the acceleration of gravity</u>.  

Now, in this case we are on Earth, so the gravity value is 9.8\frac{m}{s^{2}}  

Note the objects experience the acceleration of gravity regardless of their mass.

Nevertheless, on Earth we have air, hence <u>air resistance</u>, so the afirmation <em>"Free fall is a situation in which the only force acting upon an object is gravity" </em>is not completely  true on Earth, unless the following condition is fulfiled:

If the air resistance is <u>too small</u> that we can approximate it to <u>zero</u> in the calculations, then in free fall the objects will accelerate downwards at 9.8\frac{m}{s^{2}} and hit the ground at approximately the same time.  


5 0
3 years ago
If a student flicks a stationary 0.1 kg ball with 5N of force for 0.1 seconds. What is its final
Alisiya [41]

5m/s

Explanation:

Given parameters:

Mass of ball = 0.1kg

Force on the ball = 5N

time taken = 0.1s

Unknown:

final speed of the ball = ?

Solution:

According to newton's second law "the net force on a body is the product of its mass and acceleration".

  Force = mass x acceleration      equation 1

Acceleration =

  V is the final velocity

  U is the initial velocity

  T is the time taken

 U = O since it is a stationary body;

      a = \frac{V}{T}

Input "a" into equation 1

  F = m x \frac{V}{T}

 5 = 0.1 x \frac{V}{0.1}

 V = 5m/s

learn more:

Newton's laws brainly.com/question/11411375

#learnwithBrainly

3 0
3 years ago
For which question could a testable hypothesis be developed?
adell [148]
Does wood float in water
8 0
3 years ago
Read 2 more answers
A motorbike is travelling with a velocity of 3m/s. It accelerates at a rate of 9.3m/s for 1.8s. Calculate the distance it travel
Misha Larkins [42]

Explanation:

Consider the kinematic equation,

x  = vt +  \frac{1}{2} a {t}^{2}

where x is the distance traveled, v is the initial velocity, a is the acceleration and t is time. By plugging in known values and solving for x,

x = 3(1.8) +  \frac{1}{2} (9.3) {1.8}^{2}

through simple algebra we get

x = 20.466

where this is the distance traveled in meters.

4 0
3 years ago
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