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STALIN [3.7K]
3 years ago
14

An object of mass 11kg is falling in air and experiences a force due to air resistance of 35N. Determine the magnitude of net fo

rce acting on the object.
Physics
1 answer:
ivanzaharov [21]3 years ago
4 0

Answer:

<em>The net force acting on the object is 72.8 Nw</em>

Explanation:

<u>Net Force in Free Falling Objects</u>

When an object is falling in the air, the default force applied to it is the gravitational force or its weight. If air resistance is considered, then the net force acting on the object must take into consideration two opposed forces

F_n=W-F_a

Where F_n is the net force, F_a is the air resistance, and W is the weigh of the object

W=mg

F_n=mg-F_a

F_n=(11)(9.8)-35=72.8\ N

The net force acting on the object is \boxed{72.8 Nw}

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<h3>What are Lawson's criterion?</h3>
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7 0
1 year ago
Find the angle between forces of 41 pounds and 68 pounds given a magnitude of 87 pounds for the resultant force. (Hint: Write fo
dedylja [7]

Answer:

\theta = 76.9 degree

Explanation:

As we know that the resultant of two vectors is given as

R = \sqrt{F_1^2 + F_2^2 + 2F_1 F_2 cos\theta

here we know that

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now we have

87 = \sqrt{41^2 + 68^2 + 2(41)(68)cos\theta

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\theta = 76.9 degree

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Explanation:

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Answer:

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