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ss7ja [257]
3 years ago
7

The heat generated by a stove element varies directly as the square of the voltage and inversely as the resistance. If the volta

ge increases by a factor of 10​, what needs to be done to quadruple the amount of heat​ generated?
Physics
1 answer:
madam [21]3 years ago
3 0

Answer:

The resistance needs to be increased by a factor of 25 to quadruple the amount of heat generated

Explanation:

Let H be the heat generated by the stove element, V its voltage and R its resistance.

So, H ∝ V²/R

H = kV²/R

HR/V² = k

H₁R₁/V₁² = H₂R₂/V₂²

If H₂ = 4H₁ and V₂ = 10V₁

H₁R₁/V₁² = 4H₁R₂/(10V₁)²

H₁R₁/V₁² = 4H₁R₂/100V₁²

R₁ = R₂/25

R₂ = 25R₁

The resistance needs to be increased by a factor of 25 to quadruple the amount of heat generated.

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Calculate the specific heat of a metal from the following data. A container made of the metal has a mass of 3.8 kg and contains
OLEGan [10]

Answer:

C = 771.35 J/kg°C

Explanation:

Here, e consider the conservation of energy equation. The conservation of energy principle states that:

Heat Given by Metal Piece = Heat Absorbed by Water + Heat Absorbed by Container

Since,

Heat Given or Absorbed by a material = m C ΔT

Therefore,

m₁CΔT₁ = m₂CΔT₂ + m₃C₃ΔT₃

where,

m₁ = Mass of Metal Piece = 2.3 kg

C = Specific Heat of Metal = ?

ΔT₁ = Change in temperature of metal piece = 165°C - 18°C = 147°C

m₂ = Mass of Metal Container = 3.8 kg

ΔT₂ = Change in temperature of metal piece = 18°C - 15°C = 3°C

m₃ = Mass of Water = 20 kg

C₃ = Specific Heat of Water = 4200 J/kg°C

ΔT₃ = Change in temperature of water = 18°C - 15°C = 3°C

Therefore,

(2.3 kg)(C)(147°C) = (3.8 kg)(C)(3°C) + (20 kg)(4186 J/kg°C)(3°C)

C[(2.3 kg)(147°C) - (3.8 kg)(3°C)] = 252000 J

C = 252000 J/326.7 kg°C

<u>C = 771.35 J/kg°C</u>

5 0
3 years ago
Two identical 0.200kg mass are pressed against opposite ends of a light spring of force constant 1.75N/cm compressing the spring
arlik [135]

This type of a problem can be solved by considering energy transformations. Initially, the spring is compressed, thus having stored something called an elastic potential energy. This energy is proportional to the square of the spring displacement d from its normal (neutral position) and the spring constant k:

E_p=\frac{1}{2}kd^2= \frac{1}{2}175\frac{N}{m}\cdot 0.37^2m^2=11.98J

So, this spring is storing almost 12 Joules of potential energy. This energy is ready to be transformed into the kinetic energy when the masses are released. There are two 0.2kg masses that will be moving away from each other, their total kinetic energy after the release equaling the elastic energy prior to the release (no losses, since there is no friction to be reckoned with).

The kinetic energy of a mass m moving with a velocity v is given by:

E_k = \frac{1}{2}mv^2

And we know that the energies are conserved, so the two kinetic energies will equal the elastic potential one:

E_p = 2E_k=mv^2

From this we can determine the speed of the mass:

E_p =mv^2\implies v=\pm \sqrt{\frac{E_p}{m}}=\pm\sqrt{\frac{11.98J}{0.2kg}}=\pm 7.74\frac{m}{s}

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4 0
3 years ago
Please solve no.g <br>Anyone!???​
steposvetlana [31]

Answer:

The answer is already given... it's 31.25 cm

5 0
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Which kind of road surface is easier to see when driving at night, a pebbled uneven surface or a mirror smooth surface?
pshichka [43]
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Tamiku [17]

Answer:

I Will say the Answer is A

Explanation:

5 0
3 years ago
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