Total number of bulbs = 64
Number of defective bulbs = 10
Number of good bulbs = 64 - 10 = 54
P(5 good bulbs) = (54/64)⁵ = (27/32)⁵ = 0.428
Answer: 0.428
-9+3x
2(9-3x)/-2
-(9-3x)
-9+3x
Brainliest?
LCM between 10 and 19 is 190.
First we can find the prime factorization of 10:
2 * 5.
Prime factorization of 19:
19.
2 * 5 * 19 = 190
Answer:
11x-10
Step-by-step explanation:
1.Rearrange terms
-2(4-3x)+(5x-2)
-2(-3x+4)+(5x-2)
2.Distribute
-2(3x+4)+(5x-2)
6x-8+(5x-2)
3.Eleminate redundant parentheses
6x-8+(5x-2)
6x-8+5x-2
4.subtract the numbers
6x-8+5x-2
6x-10+5x
5.Combine like terms
6x-10+5x
11x-10
•solution
11x-10
