Answer:
μk = 0.26885
Explanation:
Conceptual analysis
We apply Newton's second law:
∑Fx = m*a (Formula 1)
∑F : algebraic sum of the forces in Newton (N)
m : mass in kilograms (kg)
a : acceleration in meters over second square (m/s²)
Data:
a= -0.9 m/s²,
g = 9.81 m/s² : acceleration due to gravity
W= 75 N : Block weight
W= m*g
m = W/g = 75/9.8= 7.65 kg : Block mass
Friction force : Ff
Ff= μk*N
μk: coefficient of kinetic friction
N : Normal force (N)
Problem development
We apply the formula (1)
∑Fy = m*ay , ay=0
N-W-25 = 0
N = 75
+25
N= 100N
∑Fx = m*ax
20-Ff= m*ax
20-μk*100
= 7.65*(-0.90 )
20+7.65*(0.90) = μk*100
μk = ( 20+7.65*(0.90)) / (100)
μk = 0.26885
Answer:
A
Explanation:
the bill of right was the outlined document.
The right answer for the question that is being asked and shown above is that:
(1) <span>b. the light will reach the front of the rocket at the same instant that it reaches the back of the rocket.
</span>(2) <span>a. the light will reach the front of the rocket before it reaches the back of the rocket.
</span>(3) <span>b. less than Δt
</span>(4) <span>c. the length of your spaceship is getting longer.
(5) </span><span>c. 1.20c</span>