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vredina [299]
3 years ago
7

Why sunlight is not reflected when passed through an electric or magnetic field

Physics
2 answers:
kicyunya [14]3 years ago
4 0
Polaroid sunglasses are familiar to most of us. They have a special ability to cut the glare of light reflected from water or glass (see Figure 1). Polaroids have this ability because of a wave characteristic of light called polarization. What is polarization? How is it produced? What are some of its uses? The answers to these questions are related to the wave character of light.

Light is one type of electromagnetic (EM) wave. As noted earlier, EM waves are transverse waves consisting of varying electric and magnetic fields that oscillate perpendicular to the direction of propagation (see Figure 2). There are specific directions for the oscillations of the electric and magnetic fields. Polarization is the attribute that a wave’s oscillations have a definite direction relative to the direction of propagation of the wave. (This is not the same type of polarization as that discussed for the separation of charges.) Waves having such a direction are said to be polarized. For an EM wave, we define the direction of polarization to be the direction parallel to the electric field.
Arlecino [84]3 years ago
3 0

Answer: N/A

Explanation:

light consists of a magnetic wave and a electric wave. Due to the perpendicular infleunce of electric wave(particle) the magnetic field is very strongly influenced it(the magnetic wave) cannot be disturbed.

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if the strength of the magnetic feild at a is 200 units and the strength of the magnetic field at b is 50 units what is the dist
IrinaVladis [17]

It would be 100 units.

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Three 10-cm-long rods form an equilateral triangle. Two of the rods are charged to + 19 nC, the third to - 19 nC.What is the ele
Sveta_85 [38]
<span>We calculate the electric field as follows:
r = </span>√<span>(3)/6 x 19 cm = .05484 m 
The angle for the triangle would be 30 on each side.
tan(30) = r/(L/2) 

E' = kQ/{r*sqrt[(L/2)^2 + r^2]} = (8.99e9 x 15e-9) / {.05484 * sqrt[(.19/2)^2 + .003]}
</span>E' <span>= 22413 N/C
The value above is the electric field strength for a single rod at the center. 

|E'| = 22413 N/C 
E = 2|E'|sin(30) + |E'| = 49000 N/C</span>
5 0
3 years ago
Un móvil, que sale desde un punto situado 3 metros a la izquierda del origen y lleva un movimiento uniforme, se sitúa a 12 metro
Verdich [7]

Answer:

x₁ = 15 m, x₂ = 12 m , x_total = 27m, v₁ = 5 m / s ,  v₂ = - 3 m / s

Explanation:

In this exercise we will use the kinematics of uniform motion

        v = d / t

let's apply this equation for the first move

        v₁ = Δx / t = (x₂-x₀) / t

        v₁ = (12- (-3)) / 3

        v₁ = 5 m / s

the distance traveled is x₁ = 15 m

Now let's analyze the return movement

        v₂ = Δx / dt

        v₂ = (0 - 12) / 4

        v₂ = - 3 m / s

The negative sign indicates that the vehicle is moving to the left

the distance traveled is x₂ = 12 m

The total dystonia is

     x_total = x₁ + x₂

     x_total = 15 +12

     x_total = 27m

In the attached we have the graphics of the movement

8 0
4 years ago
A curve of radius 55.1 m is banked so that a car of mass 1.6 Mg traveling with uniform speed 61 km/hr can round the curve withou
svp [43]

Answer:

θ = 28°

Explanation:

For this exercise We will use the second law and Newton, let's set a System of horizontal and vertical.

X axis

      Fₓ = m a

      Nₓ = m a

Where the acceleration is centripetal

      a = v² / r

The only force that we must decompose is normal, let's use trigonometry

      sin θ = Nₓ / N

      cos θ = N_{y} / N

      Nₓ = N sin θ

      N_{y} = N cos θ

Let's replace

     N sin θ = m v² / r

Y Axis

     N_{y} - W = 0

     N cos θ = mg

Let's divide the two equations of Newton's second law

     Sin θ / cos θ = v² / g r

     tan θ = v² / g r

     θ = tan⁻¹ (v² / g r)

We reduce the speed to the SI system

      v = 61 km / h (1000 m / 1 km) (1h / 3600 s) = 16.94 m / s

Let's calculate

     θ = tan⁻¹ (16.94 2 / (9.8 55.1)

     θ = tan⁻¹ (0.5317)

     θ = 28°

3 0
3 years ago
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