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Colt1911 [192]
2 years ago
14

A medieval instrument used to determine the position of the sun:

Physics
1 answer:
Stels [109]2 years ago
4 0

Answer: astrolabe

Explanation:

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Most metals are not ?
mario62 [17]
C liquid at room temperature  
4 0
3 years ago
Why potential energy become equal to kinetic energy at height
Gennadij [26K]

Answer:

because potentil energy is redy to go but its bound up

And kinetic energy is in motion

Explanation:

7 0
3 years ago
Read 2 more answers
Two objects are thrown vertically upward, first one, and then, a bit later, the other. Is it (a) possible or (b) impossible that
Studentka2010 [4]

Answer:

No, it is impossible

Explanation:

Kinematics equation:

Vf^{2} =Vo^{2} -2gy

if height is maximum:

y=H and Vf=0

so:

<h3>Vo^{2} =2gH</h3><h3>H=Vo^{2} /2g</h3>

Analysis: From the last equation we see that the maximum height depends ONLY on the initial speed. This means that if both objects reach the same maximum height, then they necessarily need to have the SAME initial velocity. If they have the same initial velocity and in order to reach the maximum height at the SAME time the only way is that they are released at the SAME TIME.

5 0
3 years ago
a car travelling at 50km/h from rest covers a distance of 10km in 40minutes. Calculate the acceleration​
Margarita [4]

Answer:

9.67\cdot 10^{-3}m/s^2

Explanation:

We can solve the problem by using the following suvat equation:

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

For the car in this problem:

u = 0 (it starts from rest)

v=50 km/h \cdot \frac{1000}{3600}=13.9 m/s is the final velocity

s = 10 km = 10 000 m is the displacement

Solving for a, we find:

a=\frac{v^2-u^2}{2s}=\frac{13.9^2}{2(10000)}=9.67\cdot 10^{-3}m/s^2

7 0
3 years ago
When a 2.40-kg object is hung vertically on a certain light spring described by Hooke's law, the spring stretches 2.92 cm.(a) Wh
Anastasy [175]

Answer:

805.48N/m

Explanation:

According to Hookes law

F = Ke

F is the force = mg

F = 2.4×9.8 = 23.52N

e is the extension = 2.92cm = 0.0292m

Force constant K = F/e

K = 23.52/0.0292

K = 805.48N/m

Hence the force constant of the spring is 805.48N/m

3 0
2 years ago
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