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Tanya [424]
4 years ago
11

A spring attached to the ceiling is stretched 2.45 meters by a four kilogram mass. If the mass is set in motion in a medium that

imparts a damping force numerically equal to 16 times the velocity, the correct differential equation for the position x (t ), of the mass at a function of time, t is
Physics
1 answer:
denpristay [2]4 years ago
6 0

Answer:

d²x/dt² = - 4dx/dt - 4x is the required differential equation.

Explanation:

Since the spring force F = kx where k is the spring constant and x its extension = 2.45 equals the weight of the 4 kg mass,

F = mg

kx = mg

k = mg/x

= 4 kg × 9.8 m/s²/2.45 m

= 39.2 kgm/s²/2.45 m

= 16 N/m

Now the drag force f = 16v where v is the velocity of the mass.

We now write an equation of motion for the forces on the mass. So,

F + f = ma (since both the drag force and spring force are in the same direction)where a = the acceleration of the mass

-kx - 16v = 4a

-16x - 16v = 4a

16x + 16v = -4a

4x + 4v = -a where v = dx/dt and a = d²x/dt²

4x + 4dx/dt = -d²x/dt²

d²x/dt² = - 4dx/dt - 4x which is the required differential equation

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When Sr and F combine to form a compound, which atom(s) will become an anion?\
labwork [276]

Answer:

Explanation:

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Flouirne is a group 7 element and it is highly electronegative. It easily draws electron to itself. With an electron, the outermost shell of Flouirne would mimic that of a noble gas.

Therefore, a combination of Sr and F would make F an electron acceptor and then an anion.

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Which scenario did not include a chemical change?
Jobisdone [24]

Answer:

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Explanation:

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What do you think a force diagram might look like for a hit that causes a concussion? Draw a diagram. Consider only the person’s
Alexandra [31]

Answer:

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5 0
3 years ago
What is the magnitude (in N/C) and direction of an electric field that exerts a 4.00 x 10^−5 N upward force on a −2.00 µC charge
emmasim [6.3K]

Answer:

The magnitude of electric field is 1.25\times10^{14}\ N/C in downward.

Explanation:

Given that,

Force F= 4.00\times10^{-5}\ N

Charge q= -2.00 μC

We know that,

Charge is negative, then the electric field in the opposite direction of the exerted force.

We need to calculate the magnitude of electric field

Using formula of electric force

F = qE

E = \dfrac{F}{q}

E=\dfrac{4.00\times10^{-5}}{-2.00\times1.6\times10^{-19}}

E=-1.25\times10^{14}\ N/C

Negative sign shows the opposite direction of electric force.

Hence, The magnitude of electric field is 1.25\times10^{14}\ N/C in downward.

8 0
4 years ago
Two ice skaters stand at rest in the center of an ice rink. When they push off against one another the 62-kg skater acquires a s
andrew-mc [135]

Answer:

48.22 kg

Explanation:

Applying the law of conservation of momentum,

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Note:  Since both skaters were initially at rest, then their total momentum  before collision is equal to zero.

And the velocity of the second skater will be in opposite direction to the first.

0 = mv+m'v'.................... Equation 1

Where m = mass of the first skater, m' = mass of the second skater, v = final velocity of the first skater, v' = final velocity of the second skater.

make v' the subject of the equation

m' = -mv/v'................. Equation 2

Given: m = 62 kg, v = 0.7 m/s, v' = -0.9 m/s (opposite direction to the first)

Substitute into equation 1

m' = -62(0.7)/-0.9

m' = 48.22 kg

5 0
3 years ago
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