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3 years ago

15

Choose all the answers that apply. Which of the following forces require physical contact? tension, air resistance, friction, ma

gnetic force, applied force

1 answer:

svet-max [94.6K]3 years ago

8 0

Answer:

I belive it would be friction applied force and tension

Explanation:

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Suppose your car is on a 5% grade, meaning that for every 100 m you travel along the road you raise or lower only 5 m in elevati

kvv77 [185]

Answer:

734.215N

Explanation:

First we calculate the angle that corresponds to a 5% slope using the Tan-1 function

$\beta = tan-1(5%)=2.86$

then we use the component that corresponds to the direction parallel to the road, additionally we must multiply by the gravity value to find the weight(g=9.81m/s^2)

Wx=M*g*sen(2.86)=1500kg*9.81*sen(2.86)=734.215N

8 0

3 years ago

Read 2 more answers

Someone please help me

Lapatulllka [165]

False... I hope that helps ;)

6 0

2 years ago

calculate the diameter of a silver wire of length 75cm , which is extended by 1.85mm when a 10kg mass is suspended from it's end

sdas [7]

Answer: $0.8\ mm$

Explanation:

Given

length of wire $l=75\ cm$

change in length $\Delta l=1.85\ mm$

mass of wire $m=10\ kg$

Young's modulus for silver $E=7.9\times 10^{10}\ N/m^2$

load on wire $F=mg$

$F=10\times 9.8=98\ kg$

change in length is given by

$\Delta l=\dfrac{Pl}{AE}$

Where A=area of cross-section

$A=\dfrac{Pl}{\Delta lE}$

$A=\dfrac{98\times 0.75}{1.85\times 10^{-3}\times 7.9\times 10^{10}}$

$A=\dfrac{73.5}{14.615\times 10^{7}}$

$A=5.029\times 10^{-7}\ m^2$

also wire is the shape of cylinder so cross-section is given by

$A=\dfrac{\pi d^2}{4}=5.029\times 10^{-7}\ m^2$

$\Rightarrow d^2=\dfrac{5.029\times 10^{-7}\times 4}{\pi }$

$\Rightarrow d^2=64.02\times 10^{-8}$

$\Rightarrow d=8\times 10^{-4}\ m$

$\Rightarrow d=0.8\ mm$

4 0

3 years ago

What is the equation of preassure <br><br><br>

oksano4ka [1.4K]

If u mean pressure, pressure = Force/Area
Correct me if I am wrong :D

8 0

2 years ago

Geologists use tools other than the law of superposition to help them with relative dating. Which statements describe those tool

White raven [17]

Answer: Cross-cutting features are always younger than the surrounding rock.

When material erodes before sediment is deposited on it, a geologic gap results.

Explanation:

The options include:

1. An unconformity is created when lava pours out on Earth’s surface.

2. Faults are the result of volcanic activity.

3. Intrusions and extrusions are sedimentary formations.

4. Cross-cutting features are always younger than the surrounding rock.

5. When material erodes before sediment is deposited on it, a geologic gap results.

The law of superposition simply states that when there is a layers of rocks, we would see that the younger layers will lie and be on top of the layers that are older.

Other tools that can help scientist with relative dating are:

• Cross-cutting features are always younger than the surrounding rock.

• When material erodes before sediment is deposited on it, a geologic gap results.

6 0

2 years ago