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NeX [460]
3 years ago
10

(a)Identify the relevant population for the below foci, and suggest the appropriate sampling

Engineering
1 answer:
nirvana33 [79]3 years ago
5 0

The relevant population for the below foci example is a small population and:

  • When a firm wants to investigate the first response of heavy fruit drink uses to a new all natural fruit drink and the best sampling to use random sampling.

<h3>What is Simple random sampling?</h3>

This is known to be a kind of probability sampling where the researcher randomly takes a subset of participants from a given population.

Note that the member of the population has an equal chance of being selected and as such, in the case above, The relevant population for the below foci example is  small population and:

  • A firm wants to investigate the first response of heavy fruit drink uses to a new all natural fruit drink and the best sampling to use random sampling.

Learn more about population from

brainly.com/question/25630111

#SPJ1

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4 years ago
Air modeled as an ideal gas enters a combustion chamber at 20 lbf/in.2
motikmotik

Answer:

The answer is "112.97 \ \frac{ft}{s}"

Explanation:

Air flowing into thep_1 = 20 \ \frac{lbf}{in^2}

Flow rate of the mass m  = 230.556 \frac{lbm}{s}

inlet temperature T_1 = 700^{\circ} F

PipelineA= 5 \times 4 \ ft

Its air is modelled as an ideal gas Apply the ideum gas rule to the air to calcule the basic volume v:

\to \bar{R} = 1545 \ ft \frac{lbf}{lbmol ^{\circ} R}\\\\ \to M= 28.97 \frac{lb}{\bmol}\\\\ \to pv=RT \\\\\to v= \frac{\frac{\bar{R}}{M}T}{p}

      = \frac{\frac{1545}{28.97}(70^{\circ}F+459.67)}{20} \times \frac{1}{144}\\\\=9.8 \frac{ft3}{lb}

V= \frac{mv}{A}

   = \frac{230.556 \frac{lbm}{s} \times 9.8 \frac{ft^3}{lb}}{5 \times 4 \ ft^2}\\\\= 112.97 \frac{ft}{s}

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