Answer:

Explanation:
From the question we are told that:
Voltage 
Power 
Initial Power factor 
Final Power factor 
Generally the equation for Reactive Power is mathematically given by
Q=P(tan \theta_2-tan \theta_1)
Since




And




Therefore



Therefore
The size of the capacitor in vars that is necessary to raise the power factor to 0.9 lagging is

Answer:


Explanation:
Given that:
x(t) = 10 sin(10t) . sin (15t)
the objective is to find the power and the rms value of the following signal square.
Recall that:
sin (A + B) + sin(A - B) = 2 sin A.cos B
x(t) = 10 sin(15t) . cos (10t)
x(t) = 5(2 sin (15t). cos (10t))
x(t) = 5 × ( sin (15t + 10t) + sin (15t-10t)
x(t) = 5sin(25 t) + 5 sin (5t)
From the knowledge of sinusoidial signal Asin (ωt), Power can be expressed as:

For the number of sinosoidial signals;
Power can be expressed as:

As such,
For x(t), Power 



For the number of sinosoidial signals;

For x(t), the RMS value is as follows:





Answer:
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Answer:
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Explanation: