When converting liquid level units to sensor output signal units, you should first convert the liquid level units to _____ units
1 answer:
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Answer:
The following command is issued
in Windows command prompt
followed by the HTTP GET
message to the “utopia.poly.edu"
web server:
> telnet utopia.poly.edu 80
As the index.html page in the web
server was not modified since
Mon, 18 May 2015 09:23:34GMT,
the following outputwas displayed
when the above commands were
issued on Sat, 23 May 2015.
The first 4 lines are the GET
message and header lines input by
the user.
The next 4 lines (starting from
HTTP/1.1 304 Not Modified) are
the response from the web server.
Explanation:
File is also attach which might help to explain the answer.
Answer:
A) For a double drainage system the time taken for total settlement will differ from that of a single drainage system, because in a double drainage case clay water escapes from both sides unlike in a single drainage case. hence water and air will be be expulsed faster for a double drainage making it attain total settlement faster.
B) for only single = 12 years
Explanation:
Given data :
ultimate clay settlement = 32 cm
settlement of clay in 3 years = 7.5 cm
Cv ( coefficient of consolidation ) = 1.5 x 10^-4 cm^2 /s
A) For a double drainage system the time taken for total settlement will differ from that of a single drainage system, because in a double drainage case clay water escapes from both sides unlike in a single drainage case. hence water and air will be be expulsed faster for a double drainage making it attain total settlement faster.
note : Total settlement is the same in both drainage system.
<u>B) Determine how long it will take for 7.5 cm of settlement to occur if there is only single </u>
applying the relation below
Tv = Cv t / H^2
where Tv = time factor , d = thickness of layer , H = drainage path
Given that Tv and Cv are constant in both cases
t ∝ H^2 hence
------ ( 1 )
t1 = time for single drainage for d meters , t2 = time for double drainage for d meters
equation 1 can be rewritten as
t1/t2 = d^2 / (d/2)^2
∴ t1 = 4t2
given that t2 = 3 years ( value gotten from question )
t1 = 4 * 3 = 12 years
Answer:
A) initial stored energy = 5x10^-4 J
B) new voltage if space is doubled will be 2000V
C) if space is doubled, stored energy becomes 2x10^-3 J
D) the extra energy comes from the work done in moving the plates further apart
Explanation:
Detailed explanation and calculation is shown in the image below
