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3 years ago

Describe one way in which entropy can increase when reactants turn into products Answer in a complete sentence

Physics

1 answer:

Ann [662]3 years ago

4 0

Answer:

Explanation:

Entropy is the degree of randomness of a system which it can increases as the temperature of the reactants is increased to yield product.

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How does an atom change it for all of its electrons are removed

Mars2501 [29]

Answer:

https://quizlet.com/170882853/atoms-flash-cards/

Explanation:

How does an atom change if all of its electrons are removed? The atom becomes positively charged. The Venn diagram compares protons with electrons. ... Protons have an electrical charge, but neutrons have no charge.

4 0

3 years ago

Can someone tell me the ans of this question quick please. will give brainliest!

Usimov [2.4K]

Answer:

64 km/h

It is a simple ratio

15 mins / 16 km

60 mins / ? km

Divide 60 / 15 to get 4

16 times 4 = 64

8 0

3 years ago

Read 2 more answers

Water flows over a section of Niagara Falls at a rate of 2.2 × 106 kg/s and falls 65 m. What is the power wasted by the waterfal

Irina-Kira [14]

Answer:

P = 1401.4 x 10⁶ W

Explanation:

Given that

Water flow rate m = 2.2 x 10⁶ kg/s

Height ,h= 65 m

Acceleration due to gravity ,g= 9.8 m/s²

The power P is given as

P= m g h

P=Power

m=Water flow rate

h=height

Now by putting the values in the above equation

P = 2.2 x 10⁶ x 9.8 x 65 W

P = 1401.4 x 10⁶ W

Therefore the power wasted will be 1401.4 x 10⁶ W.

7 0

3 years ago

A box is given a push so that it slides across the floor. How far will it go, given that the coefficient of kinetic friction is

maksim [4K]

D = v^2 / 2ug

d= 3.5^2 / 0,15 x 9.8 m/s^2

the answer should be around 4.2m

hope this helps

8 0

3 years ago

Assuming that 70 percent of the Earth’s surface is covered with water at average depth of 0.95 mi, estimate the mass of the wate

Alla [95]

Answer:

The mass of the water on earth is $5.4537\times10^{20}\ kg$

Explanation:

Given that,

Average depth h= 0.95 mi

$h=0.95\times1.609$

$h =1.528\ km$

$h=1.528\times10^{3}\ m$

Radius of earth $r= 6.37\times10^{6}\ m$

Density = 1000 kg/m³

We need to calculate the area of surface

Using formula of area

$A =4\pi r^2$

Put the value into the formula

$A=4\pi\times(6.37\times10^{6})^2$

$A=5.099\times10^{14}\ m^2$

We need to calculate the volume of earth

$V = Area\times height$

Put the value into the formula

$V=5.099\times10^{14}\times1.528\times10^{3}$

$V=7.791\times10^{17}\ m^3$

Now, 70 % volume of the total volume

$V= 7.791\times10^{17}\times\dfrac{70}{100}$

$V=5.4537\times10^{17}\ m^3$

We need to calculate the mass of the water on earth

Using formula of density

$\rho = \dfrac{m}{V}$

$m = \rho\times V$

Put the value into the formula

$m=1000\times5.4537\times10^{17}$

$m =5.4537\times10^{20}\ kg$

Hence, The mass of the water on earth is $5.4537\times10^{20}\ kg$

8 0

4 years ago