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Oxana [17]
3 years ago
11

How easy is it to die in quick sand (I know the answer to this one too i just want to see who understands)

Physics
2 answers:
matrenka [14]3 years ago
8 0
There have been 580 cases!! Wow
ludmilkaskok [199]3 years ago
6 0

Answer:

It is easy enough unless held by a machine.

Explanation:

This is because once your head gets below the sand you automatically suffocate and the more you move the more you sink meaning unless rescued by a machine you won't survive. Also when suffocating your brain sends a signal to try and breathe so you squirm to get free wich makes you sink even further. You will suffocate before anyone gets to you more than likely. Otherwise the sand fills your nostrils and lungs and if eye's are open they star to be very painful because the sand is very packed and the pressure will damage your eyes very bad.

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What's being transferred between a cell phone and a cell phone tower through radio waves?
dmitriy555 [2]

Answer:

What's being transferred is data, audios, and videos :3

Explanation:

:3

4 0
3 years ago
B. A guitar string has a length of 0.90 m. When you pluck it, it plays a “C” that has a frequency of 256 Hz. How fast is the wav
horrorfan [7]

Answer:

461  m/s

Explanation:

Given the string length of guitar, l = 0.90 m

Frequency , f = 256 Hz

Using frequency, wavelength and velocity relation as

v=f λ

Here λ is wavelength.

Now for guitar string the length must be equal to half of wavelength, so

λ = 2l

Therefor above formula becomes as  

v = f×2l

Substituting the given values, we get

v =256×2×0.90

v = 460.8 m/s = 461 m/s

Thus, the wave moving back and forth along the string with velocity 461 m/s.

5 0
3 years ago
A proton starts from rest near the surface of a sheet of charge. It experiences a force of 14.0 microNewtons towards the sheet.
Naddika [18.5K]

Answer:

The surface charge density of the sheet is 1547.516 C/m²

Explanation:

Given;

force experienced by the proton, F = 14.0 μN

Electric field near an infinite sheet with surface charge density (σ) is given as;

E = σ/2ε₀

The force of attraction the proton experienced towards the sheet;

F = Eq

F = q(σ/2ε₀) = \frac{q \sigma}{2 \epsilon_o}

where;

q is the charge of the proton

σ is the surface charge density of the sheet

ε₀ is the permittivity of free space

F = \frac{q \sigma}{2 \epsilon_o} \\\\\sigma = \frac{2F \epsilon_o}{q} \\\\\sigma = \frac{2*14*10^{-6}*8.854*10^{-12}}{1.602*10^{-19}} = 1547.516 \ C/m^2

Therefore, the surface charge density of the sheet is 1547.516 C/m²

6 0
3 years ago
If you apply 100.0 N of force to lift an object with a single, fixed pulley, then what is the resistive force?
quester [9]
<span>If you apply 100.0 N of force to lift an object with a single, fixed pulley, then the resistive force is also equivalent to 100 Newtons of force. Since the weight of the object was not mentioned, it is assumed that it has already been taken into account in the 100 N value of force. This follows Newton's law of motion of equal action and reaction.</span>
6 0
3 years ago
A net force of 15 N is applied to a cart with a mass of 2.1 kg. a. What is the acceleration of the cart? b. How long will it tak
Gennadij [26K]
The first question's answer is :
If, F=ma
Then, 15N= 2.1kg (a)
15/2.1=a
7.14=a
Therefore, acceleration = 7.14m/s^2

sorry I am not sure about the second question :-(
6 0
3 years ago
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