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Oxana [17]
3 years ago
11

How easy is it to die in quick sand (I know the answer to this one too i just want to see who understands)

Physics
2 answers:
matrenka [14]3 years ago
8 0
There have been 580 cases!! Wow
ludmilkaskok [199]3 years ago
6 0

Answer:

It is easy enough unless held by a machine.

Explanation:

This is because once your head gets below the sand you automatically suffocate and the more you move the more you sink meaning unless rescued by a machine you won't survive. Also when suffocating your brain sends a signal to try and breathe so you squirm to get free wich makes you sink even further. You will suffocate before anyone gets to you more than likely. Otherwise the sand fills your nostrils and lungs and if eye's are open they star to be very painful because the sand is very packed and the pressure will damage your eyes very bad.

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Why do blades come in different lengths in a jig saw sander?​
trasher [3.6K]

Answer:

To determine the minimum blade length, add 1" to the workpiece thickness. One type of material, and some materials can be cut by more than one type of blade. No matter the material, there's likely a jigsaw blade designed specifically for. Armed with the right blade, follow these pointers to make your work go (and cut) .

Explanation:

6 0
3 years ago
Drug abuse is best defined as __________.
Paul [167]

Answer:

Drug abuse is best defined as the nonmedical or improper use of a drug that can interfere with a healthy life.

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3 years ago
The world's largest tires have a mass of 6000 kg
nikitadnepr [17]
Okay!  Thank you for this knowledge
8 0
3 years ago
Suppose that a person has an average heart rate of 72.0 beats/min. How many beats does he or she have in 2.0 y? In 2.00 y? In 2.
Alex17521 [72]
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3 0
3 years ago
In February 1955, a paratrooper fell 362 m from an airplane without being able to open his chute but happened to land in snow, s
serious [3.7K]

Answer:

s = 0.9689 m

Explanation:

given,

Height of fall of paratroopers = 362 m

speed of impact = 52 m/s

mass of paratrooper = 86 Kg

From from snow on him = 1.2 ✕ 10⁵ N

now using formula

F = m a

a = F/m

a = \dfrac{1.2 \times 10^5}{86}

a =1395.35\ m/s^2

Using equation of motion

v² = u² + 2 a s

s =\dfrac{v^2}{2a}

s =\dfrac{52^2}{2\times 1395.35}

s = 0.9689 m

The minimum depth of snow that would have stooped him is  s = 0.9689 m

8 0
3 years ago
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