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Mama L [17]
3 years ago
6

The pressure of a gas remains constant while the temperature, volume, and internal energy of the gas increase by 57.7 Co, 1.24 x

10⁻³ m³, and 843 J, respectively. The mass of the gas is 21.6 g, and its specific heat capacity (at constant pressure) is 1080 J/(kg Co). Determine the pressure.
Physics
1 answer:
valina [46]3 years ago
8 0

Answer:

P = 405.67 kPa

Explanation:

given,

change in temperature = 57.7 °C

volume of the gas = 1.24 x 10⁻³ m³

Internal energy of the = 843 J

Cp = 1080 J/Kg.C°

mass = 21.6 g

heat capacity

Q = m Cp ΔT

Q = 0.0216 x  1080 x 57.7

Q = 1346.025 J

according to first law of thermodynamics

U = Q + W

W = Q - ΔU

PΔV = Q - ΔU

PΔV = 1346.025 - 843

P x  1.24 x 10⁻³  = 503.0256

P = 405.67 x 10³ Pa

P = 405.67 kPa

The pressure of the gas is equal to P = 405.67 kPa

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Vinil7 [7]

Battery capacity (AH) is defined as a product of the current that is drawn from the battery while the battery is able to supply the load until its voltage is dropped to lower than a certain value for each cell.

4 0
3 years ago
Hello,help me with this out please i need it hurry but please ensure your answer is correct..I attach here with my question.
lilavasa [31]

Answer:

.409 N

Explanation:

For this to balance, the moments around the fulcrum must sum to zero.

On the left you have   .21   ( is that down? I will assume it is)

      Counterclockwise moments :

        .21 * 40     +  1.0 * 20    

     Clockwise moments :

        .5 * 20     +     F * 45

these moments must equal each other

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   F = .409 N

7 0
2 years ago
Need help asap pls
ozzi
Detailed Explanation:

1) Rusting of Iron

4Fe + 3O2 + 2H2O -> 2Fe2O32H2O

Reactants :-
Fe = 4
O = 3 * 2 + 2 = 8
H = 2 * 2 = 4

Products :-
Fe = 2 * 2 = 4
O = 2 * 3 + 2 = 8
H = 2 * 2 = 4

2) Fermentation of sucrose…

C12H22O11 + H2O -> 4C2H5OH + 4CO2

Reactants :-
C = 12
H = 22 + 2 = 24
O = 11 + 1 = 12

Products :-
C = 4 * 2 + 4 = 12
H = 4 * 5 + 4 = 24
O = 4 * 2 + 4 = 12

Looking closely at the way I have taken the total number of elements on the reactants and products side, you can solve the rest.

All the Best!
8 0
2 years ago
Read 2 more answers
A water wheel rotates with a period of 2.26 s. If the water wheel has a radius of l.94 m,
Dafna11 [192]

Answer:

The correct answer is B)

Explanation:

When a wheel rotates without sliding, the straight-line distance covered by the wheel's center-of-mass is exactly equal to the rotational distance covered by a point on the edge of the wheel.  So given that the distances and times are same, the translational speed of the center of the wheel amounts to or becomes the same as the rotational speed of a point on the edge of the wheel.

The formula for calculating the velocity of a point on the edge of the wheel is given as

V_{r} = 2π r / T

Where

π is Pi which mathematically is approximately 3.14159

T is period of time

Vr is Velocity of the point on the edge of the wheel

The answer is left in Meters/Seconds so we will work with our information as is given in the question.

Vr = (2 x 3.14159 x 1.94m)/2.26

Vr = 12.1893692/2.26

Vr = 5.39352619469

Which is approximately 5.39

Cheers!

7 0
3 years ago
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ankoles [38]
Given required solution

M=10kg W=? W=Fd
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so W=12*100
W=1200J
4 0
3 years ago
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