Write the inequality: David must run his race in less than 34 seconds to win.

Graph the following equations on the graphs below. ( GRAPHING PAPER NEEDED, NOT A WEBSITE )

kodGreya [7K]

First, you want to identify the slopes and y-int.

Equation 1 = y = -2x + 2

Slope = -2

y-int. = 2 or (0,2)

Equationt 2 = y = 2x + 3

Slope = 2

Y-int. = 3 or (0,3)

To graph, first plot the y-intercepts. Then do the slopes.

Slope = -2

Down 2 over 1 (to the right)

Slope = 2

Up 2 over 1 (to the right)

Then just connect the dots in a line!

5 0

2 years ago

Between 8 a.m. and 3 p.m. on a summer day, the outdoor temperature increased by 23 degrees. Between 3 p.m. and 10 p.m., the temp

AleksAgata [21]

Answer:

46

Step-by-step explanation:

46

5 0

2 years ago

Combine the like terms to create an equivalent expression. 9y+y

dalvyx [7]

Answer: 10y

Step-by-step explanation: All variables equal one unless assigned a specific answer. So It is basically 9y+1

9y+1=10y

Final Answer: 10y

Hope this helps! :D

8 0

3 years ago

Read 2 more answers

Ben drove 230 kilometers in 3 hours, and pia drove 250 km in 3 hours. Without making any calculations, who drove faster? Explain

vovangra [49]

Pia drove faster because she went farther than Ben in 3 hours.

8 0

2 years ago

Read 2 more answers

Social Sciences Alcohol Abstinence The Harvard School of Public Health completed a study on alcohol consumption on college campu

Scilla [17]

Answer:

a) There is a 6.69% probability that a randomly selected female student abstains from alcohol.

b) If a randomly selected female student abstains from alcohol, there is a 82.87% probability that she attends a coeducational college.

Step-by-step explanation:

This is a probability problem:

We have these following probabilities:

-20.7% of a woman attending an all-women college abstaining from alcohol.

-6% of a woman attending a coeducational college abstaining from alcohol.

-4.7% of a woman attending an all-women college

- 100%-4.7% = 95.3% of a woman attending a coeducational college.

(a) What is the probability that a randomly selected female student abstains from alcohol?

$P = P_{1} + P_{2}$

$P_{1}$ is the probability of a woman attending an all-women college being chosen and abstaining from alcohol. There is a 0.047 probability of a woman attending an all-women college being chosen and a 0.207 probability that she abstain from alcohol. So:

$P_{1} = 0.047*0.207 = 0.009729$

$P_{2}$ is the probability of a woman attending a coeducational college being chosen and abstaining from alcohol. There is a 0.953 probability of a woman attending a coeducational college being chosen and a 0.06 probability that she abstain from alcohol. So:

$P_{2} = 0.953*0.06 = 0.05718$

So, the probability of a randomly selected female student abstaining from alcohol is:

$P = P_{1} + P_{2} = 0.009729 + 0.05718 = 0.0669$

There is a 6.69% probability that a randomly selected female student abstains from alcohol.

(b) If a randomly selected female student abstains from alcohol, what is the probability she attends a coedücational colege?

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

Here:

What is the probability of a woman attending a coeducational college, knowing that she abstains from alcohol.

It can be calculated by the following formula:

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

We have the following probabilities:

$P(B)$ is the probability of a woman from a coeducational college being chosen. So $P(B) = 0.953$

$P(A/B)$ is the probability of a woman abstaining from alcohol, given that she attends a coeducational college. So $P(A/B) = 0.06$

$P(A)$ is the probability of a woman abstaining from alcohol. From a), $P(A) = 0.0669$

So, the probability that a randomly selected female student attends a coeducational college, given that she abstains from alcohol is:

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{(0.953)*(0.06)}{(0.0669)} = 0.8287$

If a randomly selected female student abstains from alcohol, there is a 82.87% probability that she attends a coeducational college.

4 0

3 years ago

Write the inequality:David must run his race in less than 34 seconds to win.​

Write the inequality:David must run his race in less than 34 seconds to win.