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4 years ago

Pls help urgent Refer to the image for question

Physics

1 answer:

Temka [501]4 years ago

3 0

Answer:

Explanation:

Most probable exchange of ions occurs for option C.

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A water wave most resembles what ? O light wave O transverse wave O longitudinal wave

Flauer [41]

Answer:

i am not a point taker i help people when they need help

Explanation:

i think it is right

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3 years ago

The index of refraction for red light in water is 1.331 and that for blue light is 1.340. A ray of white light enters the water

Alex Ar [27]

Answer:

(a) 47.08°

(b) 47.50°

Explanation:

Angle of incidence = 78.9°

For blue light :

Using Snell's law as:

$\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}$

Where,

Θ₁ is the angle of incidence

Θ₂ is the angle of refraction

n₂ is the refractive index for blue light which is 1.340

n₁ is the refractive index of air which is 1

So,

$\frac {sin\theta_2}{sin{78.9}^0}=\frac {1}{1.340}$

${sin\theta_2}=0.7323$

Angle of refraction for blue light = sin⁻¹ 0.7323 = 47.08°.

For red light :

Using Snell's law as:

$\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}$

Where,

Θ₁ is the angle of incidence

Θ₂ is the angle of refraction

n₂ is the refractive index for red light which is 1.331

n₁ is the refractive index of air which is 1

So,

$\frac {sin\theta_2}{sin{78.9}^0}=\frac {1}{1.331}$

${sin\theta_2}=0.7373$

Angle of refraction for red light = sin⁻¹ 0.7373 = 47.50°.

5 0

4 years ago

How many copies of H2O are required to balance this chemical equation? CH4 + 2O2 CO2 + __H2O A. 1 B. 2 C. 3 D. 4

Step2247 [10]

You’ll need 4H20 molecules to balance the equation.

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4 years ago

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Que carro ese que está en la foto

Taya2010 [7]

Travis Scott!3&;8284$28&:!;&29395

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3 years ago

Read 2 more answers

A 50-cm-long spring is suspended from the ceiling. A 270 g mass is connected to the end and held at rest with the spring unstret

AveGali [126]

Answer:

k = 22.05 N/m

Explanation:

The potential energy of the mass is converted into potential energy of the spring.

Given:

mass m = 0.27 kg

gravitational constant g = 9.8 m/s²

distance falling/ stretching of spring h = 0.24 m

$U_{gravity} = U_{spring}\\ mgh = \frac{1}{2} kh^{2}$

Solving for k:

$k = 2mg\frac{1}{h}$

5 0

4 years ago