Answer:
f = 19,877 cm and P = 5D
Explanation:
This is a lens focal length exercise, which must be solved with the optical constructor equation
1 / f = 1 / p + 1 / q
where f is the focal length, p is the distance to the object and q is the distance to the image.
In this case the object is placed p = 25 cm from the eye, to be able to see it clearly the image must be at q = 97 cm from the eye
let's calculate
1 / f = 1/97 + 1/25
1 / f = 0.05
f = 19,877 cm
the power of a lens is defined by the inverse of the focal length in meters
P = 1 / f
P = 1 / 19,877 10-2
P = 5D
Maybe the picture helps. The blue block represents the cart with a mass of 3 kg. The person(black block) is pulling the cart to the right with a force F so that the acceleration a is 2 m/s². According to Newton's 2nd law: F = m*a.
Answer:
4400 Joules
73.33 Joules
25.9325 Joules
Explanation:
P = Power = 800 W
t = Time = 22 s
F = Force
r = Radius of arm = 90 cm
Energy
As the efficiency is 25%
Energy used in the race is 4400 Joules
Half of the energy is used in the arm
So, per stroke of paddle
The energy expenditure per arm stroke is 73.33 Joules
Displacement will be the half of the perimeter of the circle
Work done
The average force of the hand on the water is 25.9325 Joules
Answer:
Explanation:
b ) Net force = mass x acceleration
= 125 x 3.3 = 412.5 N
Forward force ( horizontal component of F ) = 585 cos 28
= 516.5 N
Net force = forward force - friction
412.5 = 516.5 - friction
friction = 516.5 - 412.5 = 104 N .
c ) Nornal force = R
Total upward force = R + 585 sin28
= R + 274.64
For balancing
R + 274.64 = mg
R + 274.64 = 585 x 9.8 = 5733
R = 5458.36 N
d ) coefficient of sliding friction be μ
μ R = friction
μ x 5458.36 = 104
μ = .019
e )
Displacement in 5 sec
s = ut + 1/2 a t²
= 0 + .5 x 3.3 x 5²= 41.25 m .
Answer: 9 Kg
Explanation:
Force = Mass x Accelaration
18 = Mass x 2
Mass = 18/2
Mass = 9 Kg