Answer:
B. twice as much kinetic energy
Explanation:
Lets take the mass of the first marble =2 m
the mass of the second marble = m
We know that velocity of particle does not depends on their mass that is the velocity of both mass will be same after dropping from the roof.
We know that kinetic energy of a mass is given as
Kinetic energy for heavier mass
Kinetic energy for light mass
KE=2 KE '
Form above two equation we can say that ,the kinetic energy for the heavier mass is twice the lighter mass.
Therefore the answer will be B.
Efficiency = (output power) / (input power)
= (3,760 joule/sec) / (4,000 joule/sec)
= 3,760 / 4,000 = 0.94 = 94%
From the laws of motions:
x = 0.5 at^2 where
x is the displacement
a is the force of gravity (constant = 9.8 m/sec^2)
t is the time taken
Since "a" is constant, therefore:
the displacement is directly proportional to the square of the time.
This means that, increasing the displacement by a factor of 4 would increase the time by a factor of (4)^2 = 16.
The height of the flare relative to ground is 202.3 m. <em>This is the sum of height reached by the flare and the 3 m platform above the ground.</em>
<h3>
Maximum height reached by the flare</h3>
The maximum height reached by the flare is determined from the principle of conservation of energy as shown below;
P.E = K.E
mgh = ¹/₂mv²
gh = ¹/₂v²
h = (v²)/(2g)
where;
- v is the speed = 225 km/h = 62.5 m/s
h = (62.5)²/(2 x 9.8)
h = 199.3 m
<h3>Height of the flare relative to ground</h3>
H = 199.3 + 3
H = 202.3 m
Thus, the height of the flare relative to ground is 202.3 m. This is the sum of height reached by the flare and the 3 m platform above the ground.
Learn more about maximum height here: brainly.com/question/12446886
(a) The angular speed of the system at the instant the beads reach the end of the rod is 9.26 rad/s.
(b) The angular speed of the rod after the after the beads fly off the rod's ends is 25.71 rad/s.
<h3>Moment of inertia through the center of the rod</h3>
I = ¹/₁₂ML²
I = ¹/₁₂ (0.1)(0.5)²
I = 0.0021 kgm²
For the beads, I = 2Mr² = 2(0.03 x 0.1²) = 0.0006 kgm²
Total initial moment of inertia, Ii = 0.0021 kgm² + 0.0006 kgm²
I(i)= 0.0027 kgm²
When the beads reach the end, I = 2Mr² = 2(0.03)(0.25)² = 0.00373 kgm²
Total final moment of inertia, I(f) = 0.0021 kgm² + 0.00373 kgm²
I(f) = 0.00583 kgm²
<h3>Speed of the system</h3>
The speed of the system at the moment the beads reach the end of the rod is calculated as follows;
<h3>Speed of the rod when the beads fly off</h3>
Learn more about moment of inertia of rods here: brainly.com/question/3406242