1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pantera1 [17]
3 years ago
8

The radius of a copper atom is 1.3⋅10^−10m. How many times N can you divide evenly a 11.1 cm long line of copper atoms until it

is reduced to a single copper atom?
Chemistry
1 answer:
Ann [662]3 years ago
7 0

Given :

Radius of copper atom , r=1.3\times 10^{-10}\ m .

Length , l = 11.1 cm = 0.0111 m .

To Find :

How many times N can you divide to reduced to a single copper atom.

Solution :

Number of time cuts required is equal to total number of atoms .

N=\dfrac{0.0111}{2\times1.3\times 10^{-10}}\\\\N=4.27\times 10^{-7}

Therefore , number of time we need to divide the rod is equal to 4.27\times 10^{-7}.

Hence , this is the required solution .

You might be interested in
What is the major product in this reaction
Butoxors [25]

Answer:

I think option A is right answer

4 0
2 years ago
To name the compound written as cucl2 you would write\
MA_775_DIABLO [31]
Copper chloride ...............
5 0
3 years ago
What would be the answer
ser-zykov [4K]

Answer:

4

Explanation:

The balanced equation for the reaction is as follows:

4Al + 3O2 --> 2(Al2O3)

4 0
3 years ago
What is the electric field (in N/C) at a point 5.0 cm from the negative charge and along the line between the two charges?
Natali [406]

Answer: E = 2.455 x 10^5 N/C

Explanation:

q1 = 1.2x10^-7C

q2 = 6.2x10^-8C

Electric field, E = kQ/r²

where k = 9.0x10^9

since the location is (27 - 5)cm from q1

hence electric field, E1 = k*q1/r²

E1= (9x10^9 x 1.2x10^-7)/(0.22)² = 22314.05 N/C

for q2:

E1 = k*q2/r²

E2 at 5cm

E2 = (9x10^9 x 6.2x10^-8)/(0.05)² = 223200 N/C

Hence, the total electric field at 5cm position is

E = E1 + E2

E = 22314.05 + 223200 = 245514.05 N/C

E = 2.455 x 10^5 N/C

4 0
3 years ago
]Which of these earthquake waves moves sideways on Earth's surface like a snake?
Anni [7]

Answer:

Love \: waves

<em><u>=>A Love wave moves sideways along the surface of the earth in a snake-like motion. Like S waves, Love waves do not move through liquid.</u></em>

4 0
2 years ago
Read 2 more answers
Other questions:
  • 1a) consider the mixed aldol condensation reaction of 1-methylcyclopentane-1-carbaldehyde (shown below) and 3,3-dimethyl-2-butan
    13·2 answers
  • Match each item to its proper disposal method. Answers to be used more than once.
    5·1 answer
  • How many milliliters (mL) are in 0.847 liters (L)
    8·1 answer
  • How many grams of F2 gas are there in a 5.00-L cylinder at 4.00 × 10^3 mm Hg and 23°C?
    12·1 answer
  • Why do pengiuns have beards
    14·2 answers
  • What did organizing information on the periodic table reveal?
    10·2 answers
  • It’s a Gas!
    10·1 answer
  • 7. Calculate moles of H2 needed to form 2.25 moles HCl in the reaction H2 + Cl2==&gt;2HCl
    11·1 answer
  • The part in the middle with a coil of wire wrapped around a metal shaft is part of an electric motor. What is it?
    10·2 answers
  • Which of the following bonds is nonpolar?<br> S-CI<br> Na--C<br> Br--CI<br> C--O
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!