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Harlamova29_29 [7]
3 years ago
11

Draw the Lewis structure for the Se and 2 H atoms.

Chemistry
1 answer:
notsponge [240]3 years ago
5 0
Here is your answer.

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A student balances the following redox reaction using half-reactions.
ICE Princess25 [194]
Answer: 6.

Explanation:

1) Aluminum

Al^0-3e^----\ \textgreater \ Al^{3+}

So each atom of aluminum lost 3 electrons to pass from 0 oxidation state to 3+ oxidation state.

2) Manganesium

Mn^{2+}+2e^{-}---\ \textgreater \ Mn

So, each ion of Mn(2+) gained 2 electrons pass from 2+ oxidation state to 0.

3) Balance

Multiply aluminum half-reaction (oxidation) by 2 and multiply manganesium half-raction (reduction) by 3:

2Al^{0}-6e^{-}---\ \textgreater \ 2Al^{3+}

3Mn^{2+}+6e^{-}---\ \textgreater \ 3Mn^{0}

4) Net equation

Add the two half-equations:

2Al^{0}+3Mn^{2+}----\ \textgreater \ 2Al^{3+}+3Mn^{0}

As you see the left side has 2 Al, 3Mn, and 3*2 positive charges.

The right side has 2 Al, 3 Mn, and 2*3 positive charges.

So, the equation is balanced.

5) Count the number of electrons involved.

As you see 2 atoms of aluminum lost 6 electrons (3 each).

That is the answer to the question. 6 electrons will be lost.
5 0
3 years ago
Read 2 more answers
Suppose you have a solution that is either an acid or a base. It doesn’t react with any metals. Is the pH of the solution more l
OverLord2011 [107]
Its more likely to be a four
4 0
3 years ago
Consider a galvanic cell consisting of the following two redox couplesAlB+ 3e Al , Mga + 2e Mg, (ag. E® = 1.676 V ) E° = 2.356 V
malfutka [58]

Answer:

0.68 V

Explanation:

For anode;

3Mg(s) ---->3Mg^2+(aq) + 6e

For cathode;

2Al^3+(aq) + 6e -----> 2Al(s)

Overall balanced reaction equation;

3Mg(s) + 2Al^3+(aq) ----> 3Mg^2+(aq) + 2Al(s)

Since

E°anode = -2.356 V

E°cathode = -1.676 V

E°cell=-1.676 -(-2.356)

E°cell= 0.68 V

4 0
3 years ago
What is the specific heat of a substance if 6527 J are required to raise the temperature of a 312 g sample by 15 degrees Celsius
Tanzania [10]

Answer:

1.395J/g°C

Explanation:

The following were obtained from the question:

Q = 6527J

M = 312g

ΔT = 15°C

C =?

Q = MCΔT

C = Q/MΔT

C = 6527/(312 x 15)

C = 1.395J/g°C

The specific heat capacity of the substance is 1.395J/g°C

3 0
3 years ago
How do you balance AlC3+H2O➡️Al(OH)3+CH4?
Alex17521 [72]
Info: Al(oh)3 might be an improperly capitalized: Al(OH)3
Error: Some elements or groups in the reagents are not present in the products: O
Error: equation Al4C3+H2O=Al(oh)3+CH4 is an impossible reaction
Please correct your reaction or click on one of the suggestions below:
Al4C3 + H2O = Al(OH)3 + CH4
5 0
3 years ago
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