What molarity is prepared when a solution contains 0.277 moles of calcium bromide in 500 mL of solution (must change mL to Liter
1 answer:
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Answer:
Explanation:
1) Molarity of the solution is (0.50/0.75)x1 = 0.66666 Mol/L
2) Molar mass of NaCl is 23+35 = 58g
Molarity = (0.5/58)/0.075 = 0.115 Mol/L
3) Molar mass of = 7x2 + 32 + 16x2 = 78g
Molarity = (734/78)/0.875 = 10.754 Mol/L
5) Molar mass of
= 207.2 + ((12x2) + (1x3) + (16x2))x4
= 207.2 + (24+3+32)x4 = 443.2g
Molarity = (0.0672/443.2)/0.1335 = 0.001135 Mol/L
6) Both are the same.
Solution 1 Molarity = 1.0/1.0 = 1 Mol/L
Solution 2 Molarity = 1.0/1.0 = 1 Mol/L
Molarities of the solutions are the same.
