Answer:
- <em>Option D. temperature</em>
Explanation:
Indeed it is generally established that <em>temperature is a measure of the kinetic energy ot the particles</em>.
The <em>kinetic energy</em> of a particle is proportional to the product of the mass and the square of the speed. Mathematically, the kinetic energy, KE, is:
Where m is the mass and v the speed of the particle.
In a sample of matter, not all the particles have the same speed, hence not all the particles have the same kinetic energy.
The kinetic energy and the temperature are related by the Boltzman equation:
Where K is a constant (Boltzman constant) and T is the absolute temperature.
Therefore, as you can see from the last equation, <em>the temperaure is a measure of the averate kinetic energy of the particles in a sample of matter</em>.
This is, at a certain temperature, every substance has the same average kinetic energy.
Answer:
The correct answer is: It loses electrons.
Explanation:
In the reactions of oxide reduction (redox), one substance gives up electrons and the other accepts them. Involved: reducing agent (yields electrons, increases its oxidation number: oxidizes) and an oxidizing agent (accepts electrons, decreases its oxidation number: reduces).
Answer:
2
Explanation:
I'm not that sure plz tell me if this is right
Answer:
2.0 x 10⁻³ M/s.
Explanation:
- The rate of the reaction is the change of the concentration of the reactants or the products with time.
<em>The rate of the reaction = - Δ[reactants]/Δt = - [(0.6 M - 1.8 M)]/(580 s - 0 s) = 2.069 x 10⁻³ M/s.</em>
Answer: The pH at the equivalence point for the titration will be 0.65.
Solution:
Let the concentration of ![[OH^-]](https://tex.z-dn.net/?f=%5BOH%5E-%5D)
be x
Initial concentration of ![[CH3NH_2]](https://tex.z-dn.net/?f=%5BCH3NH_2%5D)
, c = 0.230 M
at eq'm c-x x x
Expression of 
:
![K_b=\frac{[CH_3NH_3^+][+OH^-]}{[CH_3NH_2]}=\frac{x\times x}{c-x}=\frac{x^2}{c-x}](https://tex.z-dn.net/?f=K_b%3D%5Cfrac%7B%5BCH_3NH_3%5E%2B%5D%5B%2BOH%5E-%5D%7D%7B%5BCH_3NH_2%5D%7D%3D%5Cfrac%7Bx%5Ctimes%20x%7D%7Bc-x%7D%3D%5Cfrac%7Bx%5E2%7D%7Bc-x%7D)
Since ,methyl-amine is a weak base,c>>x so 
.
Solving for x, we get:
Given, HCl with 0.230 M , it dissociates fully in water which means ![[H^+]](https://tex.z-dn.net/?f=%5BH%5E%2B%5D)
= 0.230 M
![[OH^-]=[H^+]](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D%5BH%5E%2B%5D)
will result in neutral solution, since ![[OH^-]](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3C%5BH%5E%2B%5D)
Remaining after neutralizing ions
![[H^+]_{\text{left in solution}}=[H^+]-[OH^-]=0.230-1.07\times 10^{-2}=0.2193 M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D_%7B%5Ctext%7Bleft%20in%20solution%7D%7D%3D%5BH%5E%2B%5D-%5BOH%5E-%5D%3D0.230-1.07%5Ctimes%2010%5E%7B-2%7D%3D0.2193%20M)
![pH=-log{[H^+]_{\text{left in solution}}=-log(0.2193)=0.65](https://tex.z-dn.net/?f=pH%3D-log%7B%5BH%5E%2B%5D_%7B%5Ctext%7Bleft%20in%20solution%7D%7D%3D-log%280.2193%29%3D0.65)
The pH at the equivalence point for the titration will be 0.65.
