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wlad13 [49]
3 years ago
14

4. If an experimental value for a given observation was 415 nm while the theoretical value

Chemistry
1 answer:
Alex3 years ago
7 0

Answer: % error of observation is 4.77%

Explanation:

Given:

Observation value = 415nm

theoretical value= 435.8nm

Percent error of observation = theoretical value- observation value/ theoretical value x 100 %

= 435.8-415/435.8= 0.04772 x 100 = 4.77%

therefore % error of observation is 4.77%

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