Answer:
6.217 pounds
Explanation:
We are given;
- Density of body fats 0.94 g/mL
- Volume of fats removed = 3.0 L
We are required to determine the mass of fats removed in pounds.
We need to know that;
Density = Mass ÷ volume
1 L = 1000 mL, thus, volume is 3000 mL
Rearranging the formula;
Mass = Density × Volume
= 0.94 g/mL × 3000 mL
= 2,820 g
but, 1 pound = 453.592 g
Therefore;
Mass = 2,820 g ÷ 453.592 g per pound
= 6.217 pounds
Thus, the amount of fats removed is 6.217 pounds
Answer: number of atoms is 5.21 · 10^24
Explanation: Atomic mass of Be is 9.012 g/mol.
Number of moles n = m/M = 78.0 g / 9.012 g/mol =
Multiply this with Avogadro number Na = 6.022*10^23 1/mol
Answer:
Fe₂O₃ and C are reactants
Fe and CO₂ are products
Explanation:
Reactants:
Chemical species that are present on left side of chemical reaction equation are called reactants.
Product:
Chemical species that are present on right side of chemical reaction equation are called product.
Chemical equation:
2Fe₂O₃ + 3C → 4Fe + 3CO₂
In this reaction 2 mole of iron oxide is react with three moles of carbon and produced four moles of iron and three moles of carbon dioxide. There are equal numbers of atoms of all elements present on both side of chemical reaction so this reaction follow the law of conservation of mass.
Law of conservation of mass:
According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.
Explanation:
This law was given by french chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.
Answer:
29.41% of Calcium and 47.04% of Oxygen
Explanation:
The percent composition of an atom in a molecule is defined as 100 times the ratio between the mass of the atom and the mass of the molecule.
The mass of the molecule of the problem (Ore) is 46.28g. That means the percent composition of Calcium is:
13.61g / 46.28g * 100 = 29.41% of Calcium
And percent composition of Oxygen is:
21.77g / 46.28g * 100 = 47.04% of Oxygen
The average Kenectic energy
