The correct answer is 0.06857 moles.
C₆H₁₂O₆, that is, glucose has six carbons, twelve hydrogens, and six oxygen atoms. The atomic weight of C, H and O are as follows:
Six atoms of carbon = 6 × 12.01 g = 72.06 g
Twelve atoms of hydrogen = 12 × 1.008 g = 12.096 g
Six atoms of oxygen = 6 × 16.00 g = 96.00 g
So, the molar mass of C₆H₁₂O₆ is 72.06 g + 12.096 g + 96.0 g = 180.156 g.
It can also be written in the form as 180.16 g of C₆H₁₂O₆ is equal to 1 mole of C₆H₁₂O₆or 180.16 g/mole (as the molar mass)
Now, there is a need to find moles of 12.354 grams of C₆H₁₂O₆. So, the final conversion is:
12.354 g C₆H₁₂O₆ × 1 mole of C₆H₁₂O₆ / 180.16 g C₆H₁₂O₆
= 0.06857 moles
The half reaction with the the greater SRP has a greater tendency to gain electrons is the definition of reduction potential when considering a pair of half cell reactions.This reduction potential is measured against hydrogen electrode which is standard electrode.
Answer is: 3,3 mol of <span>nitrous oxide gas is produced in this chemical reaction.
</span>Chemical reaction: N₂ + O₂ → 2NO.
n(N₂) = 1,65 mol.
n(NO) = ?
from reaction n(N₂) : n(NO) = 1 : 2.
1,65 mol : n(NO) = 1 : 2.
n(NO) = 3,3 mol.
n - amount of substance.
When a kettle is boiling you are able to see the chemical reaction, from the stem leaving the kettle, so yes
Hope this helped : )