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alexira [117]
3 years ago
8

Name the method that used to separated amino acids from fruit juice solution

Chemistry
1 answer:
Ket [755]3 years ago
8 0
Using the method chromatography
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When h2o is added to a compound in a chemical equation, a new compound can be formed via what type of reaction?
Scorpion4ik [409]

When water is added to a compound in a chemical equation, a new compound can be formed, it is called a hydrolysis reaction.

<h3>What is hydrolysis reaction?</h3>

There are so many kinds of reaction in chemistry we know that a chemical reaction occurs between reactant molecules in order to yield products in the reactants.

The hydrolysis reaction is a breaking up reaction. In a hydrolysis reaction, water is used to break up a molecule. Hence in a hydrolysis reaction water could be regarded as one of the reactants in the reactions going on in the system.

We know that a hydrolysis is a reaction in which water reacts with another reactant molecule to yield products in the reaction. Thus, when water is added to a compound in a chemical equation, a new compound can be formed, it is called a hydrolysis reaction.

Learn more about hydrolysis:brainly.com/question/12237250

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5 0
2 years ago
Why can metals be extracted using carbon
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If a metal is less reactive than carbon, it can be extracted from its oxide by heating with carbon. The carbon displaces the metal from the compound, and removes the oxygen from the oxide. This leaves the metal.
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__________ is a condition in which water droplets in air do not freeze even when the air cools below the freezing point.
IrinaK [193]
The answer is: <span>supersaturation</span>
7 0
3 years ago
What two positions would the moon be when we have the lowest tidal range?
Shkiper50 [21]

Answer:

Quarter and half moons

Explanation:

7 0
3 years ago
You notice that the water in your friend's swimming pool is cloudy and that the pool walls are discolored at the water line. A q
kicyunya [14]

Answer:

3,78 mL of 12,0wt% H₂SO₄

Explanation:

The equilibrium in water is:

H₂O (l) ⇄ H⁺ (aq) + OH⁻ (aq)

The initial concentration of [H⁺] is 10⁻⁸ M and final desired concentration is [H⁺] = 10^{-7,2}

Thus, you need to add:

[H⁺] = 10^{-7,2} - 10^{-8} = <em>5,31x10⁻⁸ M</em>

The total volume of the pool is:

7,00 m × 18,0 m ×1,50 m = 189 m³ ≡ 189000 L

Thus, moles of H⁺ you need to add are:

5,31x10⁻⁸ M × 189000 L = 1,00<em>x10⁻² moles of H⁺</em>

These moles comes from

H₂SO₄ → 2H⁺ +SO₄²⁻

Thus:

1,00x10⁻² moles of H⁺ × \frac{1 H_{2}SO_{4} moles}{2H^+ mole} = <em>5,00x10⁻³ moles of H₂SO₄</em>

These moles comes from:

5,00x10⁻³ moles of H₂SO₄ × \frac{98,1g}{1mol} × \frac{100 gsolution}{12 g H_{2}SO_{4} } × \frac{1mL}{1,080 g} = <em>3,78 mL of 12,0wt% H₂SO₄</em>

<em></em>

I hope it helps!

5 0
3 years ago
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