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coldgirl [10]
3 years ago
5

Steam enters an adiabatic turbine at 8 MPa and 500°C at a rate of 3.2 kg/s and leaves at 20 kPa. If the power output of the turb

ine is 2.5 MW, determine the temperature of the steam at the turbine exit. Neglect kinetic energy changes. Use data from the steam tables.
Engineering
1 answer:
maw [93]3 years ago
7 0

Answer:

The temperature of the steam at turbine exit is T_{2} = 1190.26 K

Explanation:

Given data

T_{1} = 500°c = 773 K

Mass flow rate = 3.2 \frac{kg}{s}

Power output = 2.5 MW = 2500 KW

From steady flow energy equation

h_{1} + KE_{1} + PE_{1} + Q = h_{2} + KE_{2} + PE_{2} + W\\

Since Kinetic & potential energy changes are negligible.

h_{1} + Q =  h_{2} + W

Since turbine  is adiabatic so Q = 0

h_{1}  =  h_{2} + W

h_{1} - h_{2} = W

m C_{p} (T_{2} - T_{1}  )  = W

Put all the values in above equation

3.2 × 1.8723 × ( T_{2} - 773 ) = 2500

T_{2} - 773 = 417.26 K

T_{2} = 1190.26 K

This is the temperature of the steam at turbine exit.

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         r = \frac{V_4}{V_3} = \frac{V_1}{V_2}

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If the system produces enough work, the automobile and its occupants will propel. On the other hand, the efficiency of the Otto Cycle is defined as follows:

           \eta = 1-(\frac{1}{r^{\gamma - 1} } )

where:

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Ideal air is the working fluid, as stated before, for which its specific heat ratio can be considered constant.

           \gamma = 1.4

Answer:

See image attached.

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