Consider the equilibrium describing the endothermic dissolution of a solid in water. Z n ( O H ) 2 ( s ) − ⇀ ↽ − Z n 2 + ( a q )
1 answer:
Answer:
- Add more zinc hydroxide.
- Increase the temperature.
Explanation:
Hello,
Based on the given chemical reaction at equilibrium:
Thus, by considering the Le Chatelier's principle, increasing the zinc hydroxide solubility, it means favor the direct reaction, could be attained by:
- Adding more zinc hydroxide as the addition of products favor the formation of products.
- As the reaction is endothermic, the energy is considered as a reactant, therefore, increasing the temperature the direct reaction is favored.
Best regards.
You might be interested in
Answer : The oxidizing element is N and reducing element is O.
is act as an oxidizing agent as well as reducing agent.
Explanation :
An Oxidizing agent is the agent which has ability to oxidize other or a higher in oxidation number.
Reducing agent is the agent which has ability to reduce other or lower in oxidation number.
The given reaction is :
act as an oxidizing agent.
The oxidation number of N in is calculated as:
(+1)+(x)+3(-2) = 0
x = +5
And the oxidation number of N in is calculated as:
(+1)+(x)+2(-2) = 0
x = +3
From the oxidation number method, we conclude that the oxidation number reduced this means itself get reduced to
and it can act as an oxidizing agent.
act as a reducing agent.
The oxidation number of O in is calculated as:
(+1)+(+5)+3(x) = 0
x = -2
The oxidation number of O in is Zero (o).
Now, we conclude that the oxidation number increases this means itself get oxidized to
and it can act as reducing agent.