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Sphinxa [80]
1 year ago
15

If U-235 decays into Cs-135 and 4 neutrons, what other nuclide will be produced?

Chemistry
1 answer:
dmitriy555 [2]1 year ago
5 0

If U-235 decays into Cs-135 and 4 neutrons, the other nuclide that will be produced is Rb-96 (option D).

<h3>What is radioactive decay?</h3>

A radioactive decay is the process by which an unstable large nuclei emit subatomic particles and disintegrate into one or more smaller nuclei.

According to this question, a radioactive material Uranium- 235 undergoes radioactive decay into Cs- 135 and 4 neutrons (1/0n).

This means that the mass of the products we have is 135 + 4 = 139.

The mass of the nuclide left must be 235 - 139 = 96, hence, the other nuclide that will be produced is Rb-96.

Learn more about radioactive decay at: brainly.com/question/1770619

#SPJ1

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The AE of a system that releases 12.4 J of heat and does 4.2 J of work on its surroundings It is_______ jA. 16.6 B. 12.4 C. 4.2
andre [41]

ANSWER

EXPLANATION

Given that

The energy released by the system is 12.4J

Work done on the surrounding is 4.2J

Follow the steps below to find the change in energy

In the given data, energy is said to be released to the surroundings

Recall, that exothermic reaction is a type of reaction in which heat is released to the surroundings. Hence, change in enthalpy is negative

Step 1; Write the formula for calculating change in energy

\Delta E\text{ }=\text{ q }+\text{ w}

Since heat is released to the surrounding, then q = -12J

Recall, that work done by the system on the surroundings is always negative

Hence, w = -4.2J

Step 2; Substitute the given data into the formula in step 1

\begin{gathered} \text{  }\Delta E\text{ = q + w} \\ \text{  }\Delta E\text{ }=\text{ -12.4 }+\text{ \lparen-4.2\rparen} \\ \text{  }\Delta E\text{ = -12.4 - 4.2} \\ \text{  }\Delta E\text{ }=\text{ -16.6J} \end{gathered}

Therefore, the change i

3 0
1 year ago
What will happen if a peeled banana is put on a hotplate? Will it undergo a physical or a chemical change?
FinnZ [79.3K]
I would say physical, because a physical change is affecting the form of a chemical substance, but not it's chemical makeup.
6 0
3 years ago
Graph of the relationship between mass and thermal energy
elixir [45]

<em>Thermal energy</em> is the sum of the kinetic and potential energies of all the particles in an object.

Assume that you have 250 gL of water and 1 kg of water at the same temperature.

Then, each water molecule has the same kinetic energy.

The larger sample contains four times as many molecules, so it contains four times as much thermal energy.

Thus, thermal energy is directly proportional to mass.

In symbols, <em>KE </em>∝ <em>m</em> or <em>KE = km</em>.

The graph of a direct proportion is a <em>straight line passing trough the origin</em>.

It should look something like the graph below.

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3 years ago
Some covalent compounds contain atoms of just one element. true or false?
kifflom [539]
True, because diatomic elements (H2, O2, F2, Br2, I2, N2, Cl2) consist of only one element but are molecules with covalent bonds.
6 0
3 years ago
g The combustion of 1.877 1.877 g of glucose, C 6 H 12 O 6 ( s ) C6H12O6(s), in a bomb calorimeter with a heat capacity of 4.30
Mekhanik [1.2K]

Answer:

-2.80 × 10³ kJ/mol

Explanation:

According to the law of conservation of energy, the sum of the heat absorbed by the bomb calorimeter (Qcal) and the heat released by the combustion of the glucose (Qcomb) is zero.

Qcal + Qcomb = 0

Qcomb = - Qcal [1]

We can calculate the heat absorbed by the bomb calorimeter using the following expression.

Qcal = C × ΔT = 4.30 kJ/°C × (29.51°C - 22.71°C) = 29.2 kJ

where,

C: heat capacity of the calorimeter

ΔT: change in the temperature

From [1],

Qcomb = - Qcal = -29.2 kJ

The internal energy change (ΔU), for the combustion of 1.877 g of glucose (MW 180.16 g/mol) is:

ΔU = -29.2 kJ/1.877 g × 180.16 g/mol = -2.80 × 10³ kJ/mol

3 0
3 years ago
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