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RideAnS [48]
3 years ago
11

Which statement is true about this equation?

Chemistry
2 answers:
lara [203]3 years ago
3 0
The appropriate response is the fourth one. The announcement is valid about this condition beneath is in spite of the fact that it is unequal, it can be adjusted by specifically utilizing observer particles.

I hope the answer will help you. 

bulgar [2K]3 years ago
3 0

Answer:

D

Explanation:

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Classify each chemical compound listed in the table below.
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Answer:

Please find attached the table of classification of the chemical compounds, created with Microsoft Word

Explanation:

The given compounds are;

H₂SO₃ is an acid which is known as sulfurous acid

When SO₂ is added to water, we have;

SO₂ + H₂O ⇄ HSO₃ + H⁺

Therefore, H₂SO₃ is ionic

2) HI which is known as hydrogen iodide, dissolves in water as follows

HI (g) + H₂O (l)  ⇄ H₃O⁺(aq) + I⁻(aq)

Therefore, HI is able to donate hydrogen ions therefore, it is both acidic and ionic

3) KI is a salt of the alkali metal, potassium, and iodine which is a group 7 element such that it formed by the transfer of electrons from potassium to iodine making it an ionic compound

KI forms a slightly alkaline solution

4) NaClO₃ comprises of the ionic combination of sodium and chlorate ions which dissolves in water as follows;

NaClO₃ → Na⁺(aq) + ClO₃⁻(aq)

Therefore, NaClO₃ is ionic

NaClO₃ is also a strong oxidizing agent, making a Br∅nsted acid

we have;  

Sulfurous acid (also Sulfuric(IV) acid, Sulphuric acid (UK), Sulphuric(IV) acid (UK)) is the chemical compound with the formula H2SO3. There is no evidence that sulfurous acid exists in solution, but the molecule has been detected in the gas phase.[1] The conjugate bases of this elusive acid are, however, common anions, bisulfite (or hydrogen sulfite) and sulfite.

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A Question 2 (2 points) Retake question
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Answer:

3.3765 Mol O2

Explanation:

There is no work for this problem

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