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4 years ago

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Beth made wristbands and belts for a craft sale. She sold 30 of these items. Each Wristband sold for $5.50. Each belt sold for $

8.75. It’s Beth made $204 at the craft sale, how many wristbands did she sell? How many belts did she sell? Write and solve a system of equations to solve the problem. Show your work.

1 answer:

RSB [31]4 years ago

3 0

W+b=30

5.50w+8.75b=204

Use simultaneous equations to solve. Replace w with 30-b and plug into the second equation.

5.50(30-b)+8.75b=204
165-5.5b+8.75b=204
3.25b=39
b=12

She sold 12 belts.

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What is 5/16 divided by 2/3

gayaneshka [121]

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So ur answer will be 15/32

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3 years ago

What is the greatest common factor for 200,205

bixtya [17]

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3 years ago

An Article a Florida newspaper reported on the topics that teenagers most want to discuss with their parents. The findings, the

Sergio039 [100]

Answer:

The estimate is $P__{hat}} \pm E = 0.37 \pm 0.0348$

Step-by-step explanation:

From the question we are told that

The sample size is n = 522

The sample proportion of students would like to talk about school is $\r p__{hat}} = 0.37$

Given that the confidence level is 90 % then the level of significance can be mathematically evaluated as

$\alpha = 100 - 90$

$\alpha = 10\%$

$\alpha = 0.10$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table, the value is

$Z_{\frac{\alpha }{2} } =Z_{\frac{0.10}{2} } = 1.645$

Generally the margin of error can be mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\r P_{hat}(1- \r P_{hat} )}{n } }$

=> $E = 1.645 * \sqrt{\frac{0.37 (1- 0.37 )}{522 } }$

=> $E = 0.0348$

Generally the estimate the proportion of all teenagers who want more family discussions about school at 90% confidence level is

$P__{hat}} \pm E$

substituting values

$0.37 \pm 0.0348$

5 0

3 years ago

Which set of ordered pairs could represent a function? (2, 3), (2, 2), (2, 4), (2, 9), (2, –2) (1, 5), (2, 6), (1, 6), (4, 5), (

Ratling [72]

Given:

The set of ordered pairs in the options:

(a) (2, 3), (2, 2), (2, 4), (2, 9), (2, –2)

(b) (1, 5), (2, 6), (1, 6), (4, 5), (1, 4)

(c) (1, 0), (2, 0), (1, 3), (4, 3), (5, 7)

(d) (5, 1), (7, 3), (9, 5), (11, 7), (13, 9)

To find:

The set of ordered pairs that could represent a function.

Solution:

A set of ordered pairs represent a function, if there exist unique output (y-value) for each input (x-value).

In option (a) we have, five output values y=3,2,4,9,-2 for single input x=2. So, it is not a function.

In option (b) we have, three output values y=5,6,4 for single input x=1. So, it is not a function.

In option (c) we have, two output values y=0,3 for single input x=1. So, it is not a function.

In option (d), all inputs has unique output.

Therefore, the correct option is (d).

4 0

3 years ago

Read 2 more answers

The sum of a number, 1/6 of that number, 2 1/2 of that number, and 7 is 12 1/2. Find the number.

Tema [17]

Answer:

2 $\frac{1}{16}$

Step-by-step explanation:

The question state that; the sum of a number, 1/6 of that number, 2 1/2 of that number, and 7 is 12 1/2. Find the number.

First, we need to interpret and represent this statement mathematically

Let n be the number.

The sum means 'addition'

1/6 of that number is 1/6 of n = 1/6 × n = $\frac{n}{6}$

2 1/2 of that number is 2 1/2 of n = 2 1/2 × n = 5/2 × n = $\frac{5n}{2}$

So the question says that, when we add; $\frac{n}{6}$ , $\frac{5n}{2}$ and 7 all together, the value is 12 1/2

That is;

$\frac{n}{6}$ + $\frac{5n}{2}$ + 7 = 12 1/2

$\frac{n}{6}$ + $\frac{5n}{2}$ + 7 = $\frac{25}{2}$ ( changing 12 1/2 to improper fraction will give $\frac{25}{2}$ )

So we can now go ahead and solve for n

$\frac{n}{6}$ + $\frac{5n}{2}$ + 7 = $\frac{25}{2}$

subtract 7 from both-side of the equation

$\frac{n}{6}$ + $\frac{5n}{2}$ = $\frac{25}{2}$ - 7

$\frac{n + 15n}{6}$ = $\frac{25 -14}{2}$

$\frac{16n}{6}$ = $\frac{11}{2}$

$\frac{16n}{6}$ can be reduced to give us $\frac{8n}{3}$

$\frac{8n}{3}$ = $\frac{11}{2}$

Cross multiply

8n × 2 = 11× 3

16n = 33

Divide both-side of the equation by 16

$\frac{16n}{16}$ = $\frac{33}{16}$

(On the left-hand side of the equation, 16 will cancel-out 16 leaving us with just, while on the right-hand side of the equation 33 will be divided by 16)

n = $\frac{33}{16}$ = $2\frac{1}{16}$

Therefore the number is $2\frac{1}{16}$

5 0

4 years ago