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Effectus [21]
3 years ago
12

3n^2−2n−8 Factoring trinomials II

Mathematics
1 answer:
masya89 [10]3 years ago
6 0

Answer:

(3n + 4) (n-2)

Step-by-step explanation:

Are you asking to factor this 3n^2 - 2n -8 ?

If so the best way to do this problem  is with the X method.

                                     top:    3*(-8)

    left:  factor of 3*-8                             right:  factor of 3*-8

                                   bottom:  -2

try the factors  4 and -6  because   4*-6 =  3 *-8 = -24

Because   notice that  4 + -6 = -2

so:

    3n^2 -2n - 8  can be rewritten as    3n^2  -6n + 4n  - 8

We should first use Distributive property to factor:  3n^2  -6n + 4n  - 8

3n^2  -6n + 4n  - 8  =   3n (n - 2)  +  4(n - 2)

Now we factor by grouping here :   (3n + 4) (n-2)  

I factored out the group  (n-2)

Therefore:  (3n + 4) (n-2) = 3n^2 -2n - 8

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When Sam’s little brother was born, he was 18 inches tall. Each year, he grows an average of 3 inches. Sam’s brother continues t
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Answer:

45

Step-by-step explanation:

year 1 : 18 in

every year after that he grows 3 in so 3 in so 3x9=27

then 27+18=45

8 0
3 years ago
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Step-by-step explanation:

3 0
3 years ago
0.5,1/5,0.35,12/25,4/5 least to greatest
kykrilka [37]
First make sure that the divider is the same

5/10     ,   1/5       ,   35/100     , 12/25      , 4/5

50/100   ,  20/100 . 35/100     ,   48/100 , 80/100

So the least to greatest would be :
1/5   , 12/25  , 0.5  ,  4/5

Hope this helps
3 0
4 years ago
Factor: 10x^3-35x^2-12x+42<br><br> I'll give brainliest :) but please show all work.
alexandr402 [8]

Answer:

\left(2x-7\right)\left(5x^2-6\right)

Explanation:

\hookrightarrow\sf 10x^3-35x^2-12x+42

using associative property, separate

\hookrightarrow\sf \left(10x^3-35x^2\right)+\left(-12x+42\right)

take common term, factorise

\hookrightarrow\sf 5x^2\left(2x-7\right)-6\left(2x-7\right)

final answer

\hookrightarrow\sf \left(2x-7\right)\left(5x^2-6\right)

5 0
2 years ago
Read 2 more answers
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