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k0ka [10]
3 years ago
5

What does carbon dioxide do when released into the air

Chemistry
2 answers:
Strike441 [17]3 years ago
5 0
There are both natural and human sources of carbon dioxide<span> emissions. Natural sources include decomposition, ocean </span>release<span> and respiration. Human sources come from activities like cement production, deforestation as well as the burning of fossil fuels like coal, oil and natural gas.
       hopes this helps </span>
Brut [27]3 years ago
3 0
It dissolved into water, then plants uses that carbon create glucose (sugar). Hope this helped
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Two hundred grams of a substance requires 9.76kj of heat to raise its temperature from 25 C to 45 C. It has a specific heat of 2
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B. Gasoline
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3 years ago
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The following chemical equation is unbalanced. When the equation is balanced, what is the coefficient for pure calcium (Ca)? A.
erik [133]
<span>3Ca + 2AlPO4 -> 2Al + Ca3(PO4)2 . . .the coefficient for Ca is 3.</span>
5 0
3 years ago
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How many grams of H2O will be formed when 36.8 g H2 is mixed with 40.2 g O2 and allowed to completely react to form water
Artemon [7]

Answer:

45.225 grams of H₂O will be formed when 36.8 g H₂ is mixed with 40.2 g O₂

Explanation:

The balanced reaction is:

2 H₂ + O₂ → 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

  • H₂: 2 moles
  • O₂: 1 mole
  • H₂O: 2 moles

Being the molar mass of the compounds:

  • H₂: 2 g/mole
  • O₂: 32 g/mole
  • H₂O: 18 g/mole

then, by reaction stoichiometry, the following amounts of reactant and product mass participate:

  • H₂: 2 moles* 2 g/mole= 4 g
  • O₂: 1 mole* 32 g/mole= 32 g
  • H₂O: 2 moles* 18 g/mole= 36 g

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use the reaction stoichiometry of the reaction and a simple rule of three as follows: if by stoichiometry 4 g of H₂ react with 32 g of O₂, 36.8 g of H₂ with how much mass of O₂ will it react?

mass of O_{2} =\frac{36.8  grams of H_{2}*32  grams of O_{2} }{4  grams of H_{2}}

mass of O₂=294.4 grams

But 294.4 grams of O₂ are not available, 40.2 grams are available. Since you have less mass than you need to react with 36.8 grams of H₂, oxygen O₂ will be the limiting reagent.

Then you can apply the following rule of three: if by stoichiometry 32 grams of O₂ form 36 grams of H₂O, 40.2 grams of O₂ how much mass of H₂O will it form?

mass of H_{2}O=\frac{40.2 grams of O_{2} *36 grams of H_{2}O }{32 grams of O_{2} }

mass of H₂O= 45.225 grams

<u><em>45.225 grams of H₂O will be formed when 36.8 g H₂ is mixed with 40.2 g O₂</em></u>

8 0
2 years ago
What is the [h3o+] for a solution at 25°c that has poh = 5.640?
jonny [76]

Answer:

= 4.37*10^-9 M

Explanation:

We know that;

pH + pOH = 14

Therefore;

pH = 14 - pOH

Which means; pH = 14 - 5.64

                               = 8.36

But;

pH = -log[H3O+]

Thus;

8.36 = -log[H3O+]

[H3O+] =  10^(-8.36)

        = 4.37*10^-9 M

5 0
3 years ago
A container with a volume of 893L contains how may moles of air at STP?
Vadim26 [7]

Answer:

i think 54

Explanation:

7 0
3 years ago
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