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timofeeve [1]
3 years ago
5

How many moles are in 3.4 x 10^-7 molecules of silicon dioxide, SiO2?​

Chemistry
1 answer:
avanturin [10]3 years ago
7 0

Answer:

Approximately 5.646 * 10^-17 moles

Explanation:

Avagardo's number is approximately 6.022 * 10^23 molecules. Therefore, dividing 3.4 * 10^7 by avagadro's number yields approximately 5.646 * 10^-17 moles. Hope this helps

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<em>V = 151 mL = 151 cm³</em>
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d = m/V
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Answer:

5.28 L

Explanation:

Step 1:

Data obtained from the question.

Volume of acid (Va) = 5.12L

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Volume of base (Vb) =.?

Step 2:

The balanced equation for the reaction

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From the balanced equation above,

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Step 3:

Determination of the volume of the base.

This is illustrated below:

MaVa/MbVb = nA/nB

2.75 x 5.12 / 4 x Vb = 2/3

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Divide both side by 4 x 2

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Vb = 5.28 L

Therefore, the volume of the base is 5.28 L

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