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notka56 [123]
3 years ago
14

Show the calculation of the final temperature for a 20.8 gram piece of iron heated to 100oC which has been added to a 55.3 gram

sample of water at 25.3oC in a coffee cup calorimeter.
c (water) = 4.184 J/g oC; c (Fe) = 0.449 J/g oC
Chemistry
1 answer:
GrogVix [38]3 years ago
5 0

Answer:

Final Temperature = 28.2 oC

Explanation:

Information given;

Mass of Iron = 20.8g

Initial Temperature of Iron = 100C

Mass of water = 55.3g

Initial temperature of water = 25.3 C

The presence of a coffee cup calorimeter hints that there is no heat loss to the surrounding and that the iron and water are at thermal equilibrium.

Thermal equilibrium means that there is no heat transfer going on between the bodies, which simply means that the bodies are at the same temperature.

Hence, both bodies would the same final temperature (T2)

H = M * C * ΔT (For iron)

H = 20.8 * 0.449 * ( 100 - T2)

H = 9.3392 ( 100 - T2)

H = 933.92 - 9.3392T2

H = M * C * ΔT (For water)

H = 55.3 * 4.184 * (T2 - 25.3)

H = 231.3752 (T2 - 25.3)

H = 231.3752T2 - 5853.79

Since they are in thermal equilibrium it means H (Iron) = H (water).

This leads to;

933.92 - 9.3392T2 = 231.3752T2 - 5853.79

231.3752T2 +  9.3392T2  = 5853.79 + 933.92

240.7144 T2 = 6787.71

T2 = 28.2 oC

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Which of the following pairs of elements is most likely to form an ionic compound?
Scrat [10]

Explanation:

magnesium and sodium because they are minerals and part of iron

5 0
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An iron bar at 200c is placed in thermal contact with an identical iron bar at 120c in an isolated system
Step2247 [10]

Conduction: In the conduction, the heat is transferred from the hotter body to the colder body until the temperature on both bodies are equal.

In thermal equilibrium, there is no heat transfer as the heat is transferred till the temperature on the bodies are not same.

In the given problem, an iron bar at 200°C is placed in thermal contact with an identical iron bar at 120°C in an isolated system. After 30 minutes, the thermal equilibrium is attained. Then, the temperature on both iron bars are equal.Both iron bars are at 160°C in an isolated system.

But in an open system, the temperatures of the iron bars after 30 minutes would be less than 160°C. There will be heat lost to the surrounding. The room temperature is 25°C. There will be exchange of the heat occur between the iron bars and the surrounding. But It would take more than 30 minutes for both iron bars to reach 160°C because heat would be transferred less efficiently.

7 0
3 years ago
Read 2 more answers
Determine the empirical formula of the following compound if a sample contains 0.104 molK, 0.052 molC, and 0.156 molO;?
faltersainse [42]

Answer:

K₂CO₃    

Explanation:

Given parameters:

Number of moles of K = 0.104mol

Number of moles of C = 0.052mol

Number of moles of O = 0.156mol

Method

From the given parameters, to calculate the empirical formula of the elements K, C and O, we reduce the given moles to the simplest fraction.

Empirical formula is the simplest formula of a compound and it differs from the molecular formula which is the actual formula of a compound.

  • Divide the given moles through by the smallest which is C, 0.052mol.
  • Then approximate values obtained to the nearest whole number of multiply by a factor to give a whole number ratio.
  • This is the empirical formula

Solution

Elements                             K                       C                    O

Number of moles            0.104                0.052            0.156

Dividing by the

smallest                       0.104/0.052     0.052/0.052  0.156/0.052

                                            2                           1                     3

The empirical formula is K₂CO₃      

3 0
3 years ago
The reaction A( g ) ⇌ 2 B( g ) A(g) ⇌ 2 B(g) has an equilibrium constant of K = 0.010 K = 0.010. What is the equilibrium constan
Over [174]

Answer:

K = 10

Explanation:

Using Hess's law, it is possible to obtain the equilibrium constant, K, of a reaction using K of similar reactions. For example:

<em> If A ⇄ B K = X</em>

B ⇄ A K = 1/X

2A ⇄ 2B K = X².

Thus, if A(g) ⇄ 2B(g) K = 0.010

2B(g) ⇄ A(g) K = 1 / 0.010; K = 100

B(g) ⇄ A(g) K = √100 = 10

<h3>K = 10</h3>
5 0
3 years ago
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